Help with output operator

I am trying to take the following header and implementation files and changed them so that an output operator, <<, can be used. The code Point P(14.3, 4.2);
                       cout<<P;
should produce an utput of (14.3, 4.2). What modifications would be necessary to make this happen?
here is my code so far:

header:
#ifndef POINT_H
#define POINT_H
#include <iostream>
#include <conio>

using namespace std;

class Point
{
public:
Point (); //constructor
Point (double, double); //constructor

double GetX () const;
double GetY () const;

private:
double x;
double y;
};
#endif

and the implementation file:
#pragma hdrstop
#include "point.h"
Point::Point ()
{
     x=0;
     y=0;
}

Point::Point ( double InputX, double InputY)
{
x=InputX;
y=InputY;
}

double Point::GetX () const
{
      return x;
}

double Point::GetY () const
{
     return y;
}

please help me out on this
jba6511Asked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

jkrCommented:
You'll need a global 'operator<<()', as you cannot add that functionality to 'cout', e.g.

ostream& operator << ( ostream& r, Point& l) {

  r << "(" << l.GetX() << ", " << l.GetY() << ")";

  return r;
}

As the above only uses public members of 'Point', you won't even need to make it a 'friend'.
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
jba6511Author Commented:
what would need to be done if i was to make it a friend then?
0
jkrCommented:
>>what would need to be done if i was to make it a friend then?

You'd use

class Point
{
public:

friend ostream& operator << ( ostream& r, Point& l);

//...
};

in your class definition - but, this is not even necessary...

0
jkrCommented:
Do you have any further problems with this one?
0
tinchosCommented:
No comment has been added lately, so it's time to clean up this question.
I will leave the following recommendation for this question in the Cleanup topic area:

Accept: jkr {http:#9645613}

Please leave any comments here within the next four days.
PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

Tinchos
EE Cleanup Volunteer
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C++

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.