Loading arrays from text file...again :P

I asked a very similar qustion earlier here and got the answer I needed,
but now my program has changed and I'm running into some small problems.
I can load the values from the file into the 2d array perfectly, but when I try to
run an if to test the values i get screwed. This code should printf("%s", textures[0]); but
prints nothing.  the first value of map.txt is 9, i.e.
cat map.txt
9 0 0 1 1 3 3 4 5 6 7

#include <string.h>
#include <stdio.h>
#include <stdlib.h>
using namespace std;

int main () {
  FILE * pFile;
  long lSize;
  char * buffer;

  pFile = fopen ("map.txt" , "rb" );
  if (pFile==NULL) exit (1);
  fseek (pFile , 0 , SEEK_END);
  lSize = ftell (pFile);
  rewind (pFile);
.
  buffer = (char*) malloc (lSize);
  if (buffer == NULL) exit (2);
  fread (buffer,1, lSize,pFile);

  char * pch;
  pch = strtok (buffer," ");

  int x = 0;
  int y = 0;

  char* matrix[15][20];

  while (pch != NULL)
  {
    if(y <= 19)
    {
      matrix[x][y] = pch;
      pch = strtok (NULL, " ,.");
      y++;
    }
    else
    {
     y = 0;
     x++;
    }
  }
/* ======================================================================*/
  char *textures[] = {".\\images\\stone.bmp", ".\\images\\woodtile.bmp"};
 
  for(int row = 0; row<15; row++){
    for(int col = 0; col<20; col++){
      if(matrix[0][0] == "9"){        //test matrix[0][0] to see if to equals "9"
        printf("%s", textures[0]);    //if it does then printf
      }
    }
  }
/* ======================================================================*/
  fclose (pFile);
  free (buffer);
  return 0;
}
w00tAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

w00tAuthor Commented:
that period around line 19 shouldn't be there :P
ExceterCommented:
>> char *textures[] = {".\\images\\stone.bmp", ".\\images\\woodtile.bmp"};
>>
>> ...
>> 
>> printf("%s", textures[0]);    //if it does then printf

textures is a char array. Its type is char*. textures[0] is a char, not a char*. You are attempting to display a string using the first char in the array as the pointer to the array. You could do this by saying,

printf("%s", &textures[0]);

but it is easiuer to simply say,

printf("%s", textures);

Exceter
ExceterCommented:
Oops, strike that, I didn't notice that textures had multiple dimensions...
OWASP: Forgery and Phishing

Learn the techniques to avoid forgery and phishing attacks and the types of attacks an application or network may face.

ExceterCommented:
Here's the actual culprit, unless the sleepy seed demon is still haunting me,

>> char* matrix[15][20];

...

>>      if(matrix[0][0] == "9"){        //test matrix[0][0] to see if to equals "9"
>>        printf("%s", textures[0]);    //if it does then printf

matrix[0][0] is a char. "9" is a null terminated string containing the character 9 and a terminating null byte. Therefore its type is char*, not char. Replacing the double quotes with single quotes tells the compiler that this is a single character and not a string. Therefore, this should read,

if(matrix[0][0] == '9')
    printf("%s", textures[0]);

Cheers!
Exceter
ExceterCommented:
Grrr....

>> char* matrix[15][20];

Okay, I'm getting annoyed with myself now... This is an array of char* pointers and not chars...

>>      if(matrix[0][0] == "9"){        //test matrix[0][0] to see if to equals "9"
>>        printf("%s", textures[0]);    //if it does then printf

Understand that this comparison is still wrong, I simply stated the wrong reason for this. Both matrix[0][0] and "9" are char* pointers to a string. However, they can point to different arrays that contain the same data. Therefore, the pointer value of "9" is not equal to the pointer value for matrix[0][0] and the comparison fails. The actual data in the arrays is never compared. You need to use the strcmp function for this task, for example,

if( strcmp( matrix[0][0], "9" ) == 0 ) // If the data in the strings are equal, print textures[0]
   printf("%s", textures[0]);

I should have read your question more carefully from the beginning. My apologies.

Cheers!
Exceter

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
tinchosCommented:
No comment has been added lately, so it's time to clean up this question.
I will leave the following recommendation for this question in the Cleanup topic area:

Accept: Exceter {http:#9647391}

Please leave any comments here within the next four days.
PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

Tinchos
EE Cleanup Volunteer
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C++

From novice to tech pro — start learning today.