user-defined method

I'm trying to write a program that prompts the user to input a sequence of characters and outputs the number of vowels.
I have to use the method isVowel.

and i got 2 errors:
1) public static boolean isVowel(char ch)  --> illegal start of expression
2) if (isVowel(userInput.charAt(i)) == true) --> cannot resolve symbol

here's my codes:
import java.io.*;

public class Vowel
{
      static BufferedReader keyboard = new BufferedReader(new InputStreamReader(System.in));
      
      public static void main(String[] args)throws IOException
      {
            //declares variables
            int stringLength;
            int counter = 0;
            int i;

        String inputLine;

            System.out.println("enter a sequence of characters: ");
            System.out.flush();
            inputLine = keyboard.readLine();
            
            //evaluates the length of user's input
            stringLength = inputLine.length();

            for(i = 0; i <= (stringLength - 1); i++)
            {
                  //calls method isVowel
                  if (isVowel(userInput.charAt(i)) == true)
                  {
                        counter++;
                  }
        }

        System.out.println("The number of vowels in this sequence: " + counter);

            //creates method isVowel
            public static boolean isVowel(char ch)
            {
                  if((ch == 'a')||(ch == 'e')||(ch == 'i')||(ch == 'o')||(ch == 'u'))
                  {
                        return true;
                   }
              
                    else
                   {
                    return false;
              }
          };
      }
}

please teach me.....
crystalfish0318Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

sre23Commented:
>> if (isVowel(userInput.charAt(i)) == true)
This should be:

if(isVowel(inputLine.charAt(i)) == true)


And you second problem is you just have a parenthesis in the wrong place.  Your first method main() doesn't have an ending parenthesis.  Here is the correct code:

import java.io.*;

public class Vowel
{
     static BufferedReader keyboard = new BufferedReader(new InputStreamReader(System.in));
     
     public static void main(String[] args)throws IOException
     {
          //declares variables
          int stringLength;
          int counter = 0;
          int i;

        String inputLine;

          System.out.println("enter a sequence of characters: ");
          System.out.flush();
          inputLine = keyboard.readLine();
         
          //evaluates the length of user's input
          stringLength = inputLine.length();

          for(i = 0; i <= (stringLength - 1); i++)
          {
               //calls method isVowel
               if (isVowel(inputLine.charAt(i)) == true)
               {
                    counter++;
               }
        }

        System.out.println("The number of vowels in this sequence: " + counter);
    }

          //creates method isVowel
          public static boolean isVowel(char ch)
          {
               if((ch == 'a')||(ch == 'e')||(ch == 'i')||(ch == 'o')||(ch == 'u'))
               {
                    return true;
                 }
             
                  else
                 {
                  return false;
             }
         };
     
}




0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Java

From novice to tech pro — start learning today.