how to Upload and resize an image

I hope this is a relatively easy request... what i want to do is i want to upload an image to my website and i want it to resize it when it uploads.  So for example on my form i fill out the name, location(directory to where it's going) and pick which image i want to upload then click submit... then i would like it to resize the file ... i've heard of using functions like imageCopyResize() but am unsure how... php.net didn't give very good examples and i was hoping someone could assist me or give me some example code.

Thanks Again

Adam
Adam409Asked:
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lozlozCommented:
hi,

i use this function, came from the php manual i think. it's for jpgs only

/* resizeToFile resizes a picture and writes it to the harddisk
*  
* $sourcefile = the filename of the picture that is going to be resized
* $dest_x   = X-Size of the target picture in pixels
* $dest_y   = Y-Size of the target picture in pixels
* $targetfile = The name under which the resized picture will be stored
* $jpegqual   = The Compression-Rate that is to be used
*/

function resizeToFile ($sourcefile, $dest_x, $dest_y, $targetfile, $jpegqual = "80")
{


/* Get the dimensions of the source picture */
$picsize=getimagesize("$sourcefile");

$source_x = $picsize[0];
$source_y  = $picsize[1];
$source_id = imageCreateFromJPEG("$sourcefile");

/* Create a new image object (not neccessarily true colour) */

$target_id=imagecreatetruecolor($dest_x, $dest_y);

/* Resize the original picture and copy it into the just created image
  object. Because of the lack of space I had to wrap the parameters to
several lines. I recommend putting them in one line in order keep your
  code clean and readable */


$target_pic=imagecopyresampled($target_id,$source_id,
                             0,0,0,0,
                              $dest_x,$dest_y,
                              $source_x,$source_y);

/* Create a jpeg with the quality of "$jpegqual" out of the
  image object "$target_pic".
  This will be saved as $targetfile */

imagejpeg ($target_id,"$targetfile",$jpegqual);

return true;

}

you need to make sure your form is multipart/form-data, eg.
<form enctype="multipart/form-data" action="<? print $_SERVER["PHP_SELF"]; ?>" method="POST">

then you have your input type="file" and input type="filename" or something

from the script processing the data, you can access the file through the $_FILES global variable (in versions of php after 4.1.0, $HTTP_POST_FILES before). so for example you may have copy($_FILES["filename"]["tmp_name"], "../images/yourdirectory/" . $_POST["filename"]); first. then you can use the function in this way:

resizeToFile("../images/yourdirectory/" . $_POST["filename"]); , "150", $height, "../images/yourdirectory/thumbnails/" . $_POST["filename"]);

cheers,

loz

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zero303Commented:
http://www.devarticles.com/art/1/608

Following link may be of use....
Adam409Author Commented:
Thanks lozloz

I tried to get a few of those functions to work like imagecreatetruecolor() and it said at www.php.net "Note: This function was added in PHP 4.0.6 and requires GD 2.0.1 or later".  I did a phpinfo() on what version of GD Library my web hosting company is using and it said GD Version 1.6.2 or higher... i'm not quite sure what this means exactly ... does this mean that this function should work or is the GD Library version not recent enough??

Adam
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lozlozCommented:
it looks like you need to update your gd version. to be honest, it might be worth asking them to upgrade their version of php since 4.0.6 is pretty old..

loz
Adam409Author Commented:
That 4.0.6 was what they said was needed on php.net not what my webhosting company is currently running... but my version of GD does need to be upgraded i think.  

Anyways thanks for all your help lozloz

Adam
lozlozCommented:
alright, tell me if its still not working after the upgrade

loz
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