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# Converting letters to numbers

Posted on 2003-10-30
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This is probably quite simple, but say I wanted to convert A-Z to 10-36.

Can I do this any way other than \$string =~ s/A/10/i; , etc. ?

Thanks,
Nik
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Question by:OKSD
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Expert Comment

ID: 9654142
\$string=~s/([A-Z])/10+ord(\$1)-ord('A')/eg;
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Author Comment

ID: 9654215
Ok, I'll try that, thanks. Could you explain a bit of that? I understand some of it, but what is +ord and -ord? and what is the 'e' appended at the end?
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Author Comment

ID: 9654235
And how would you effect the opposite? i.e., numerical to text.

Thanks
0

LVL 84

Expert Comment

ID: 9654253
perldoc -f ord
ord EXPR
ord     Returns the numeric (the native 8-bit encoding,
like ASCII or EBCDIC, or Unicode) value of the
first character of EXPR.  If EXPR is omitted, uses
\$_.

For the reverse, see "chr".  See perlunicode and

perldoc perlop
s/PATTERN/REPLACEMENT/egimosx

Options are:

e   Evaluate the right side as an expression.
g   Replace globally, i.e., all occurrences.
i   Do case-insensitive pattern matching.
m   Treat string as multiple lines.
o   Compile pattern only once.
s   Treat string as single line.
x   Use extended regular expressions.
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Expert Comment

ID: 9654300
s/(\d\d)/chr(\$1-10+ord('A'))/eg;
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Author Comment

ID: 9654311
Could you print an example of the reverse please?

Thanks
0

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Accepted Solution

ozo earned 150 total points
ID: 9654356
\$_ = join' ','A'..'Z',"\n";
s/([A-Z])/ord(\$1)-ord('A')+10/eg;
print;
s/(\d\d)/chr(\$1+ord('A')-10)/eg;
print;
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Author Comment

ID: 9654363
Ok, works perfectly. Thank you very much! ;)

-Nik
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