finding sum of nxn matirx data


    i have an array of pixel data. x,y value of each pixel is known.
   I have to find the sum of nxn pixels around the given pixel(including the pixel)

  that is for the pixel at (x,y). 3x3 sum will be

This calculation should be dynamic, that is for any nxn , the sum should be computed.
i would like to know the way to go abt doing this.

Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

you have to create a function:

function filter_pixel(x,y,n)
if x>1 AND y>1 and x<n-1 and y<n-1 then
all the border' case

end if
end function

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Why are you trying to do this?  Is this homework perhaps?

Try it with a nested loop

funct filterpixel(x,y,n)
int sum=0
for int i=x-n to x+n
     for int k=y-n to y+n
          sum += getPixelValueAtPosition(i,k)
return sum
end funct

and implement a function named getPixelValueAtPosition() that checks if pixel coordinates are inside your image and returns the pixel value for it.

Above code is not valid for any programming language, so if it is homework, it's not a complete solution. Is that ok this way, mlmcc?
You will need to subtract the value at (x,y)

It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today

From novice to tech pro — start learning today.