asked on

msxml4.dll error '80020005' Type mismatch

Hi!

I have an asp page with the following statements:

Dim ipAddress

Call oXslProc.addParameter("ipAddress", Server.Variables("REMOTE_HOST"))

I an xsl page with the following statements:
<xsl:param name="ipAddress"/>

Requesting IP Address: <xsl:value-of select="$ipAddress"/>  Requested by: <xsl:value-of select="$username"/>

I am getting the following error:
msxml4.dll error '80020005'
Type mismatch.

Any ideas?

Chuck

Brad Dobyns, CSM

Well, one area where that error occurs is due to a field in your database has a field type different than what you are trying to post. Other things include:

- a string expected, but not enclosed in '
- a double or float not enclosed in '
- an integer enclosed in '
- an '=' operator for string instead of LIKE

Those are just some of the possibilities. Does it give a line where the error occured?

Brad

TrueBlue

ASKER

Hi!

This is the line that it errored out on:

Call oXslProc.addParameter("ipAddress", Server.Variables("REMOTE_HOST"))

Chuck

ASKER CERTIFIED SOLUTION

fozylet

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TrueBlue

ASKER

Hi fozylet!

Your suggestion got me very close.

Here is the answer.

Without the request if gives a not supported by object error.

Call oXslProc.addParameter("ipAddress", CStr(Request.ServerVariables("REMOTE_HOST")))

Thank you for the help.

Chuck

fozylet

Oops, I didn't see the function part!
Thanks for the points :)