streaming STL map

I need to stream a STL map via the MarshalInterface method on IMarshal .How do we give the size specifications for STL map?
e.g typedef map<string,string> MAPSTRTOSTR
MAPSTRTOSTR mSTLString;

somewhere later on,

mSTLString.insert(MAPSTRTOSTR::value_type("unity","is strength");

Now to pass this map into the Write method of IStream interface what do i give the size of the map as ?

ranadhirAsked:
Who is Participating?
 
ChmodCommented:
PAQ'd & 30 points refunded

Chmod
Community Support Moderator @ Experts Exchange
0
 
_ys_Commented:
Sorry, but I do have to question your motives here. COM is supposed to be platform and language independant.

If you want to return a collection the standard IEnumXxxx style implementation would suit better.
0
 
ranadhirAuthor Commented:
There is an exisitng  class which reads data from a data storage(in this case  , a set of files ) and stores it into a map.
Now the idea is add custom marshalling support to this class,to stream the stored map to the client.The objective was to prevent any round network  trips when the client retrieves records from the map.
This idea was tested fine with a normal data-type like long etc. - but to implement this with a map;we needed to determine how to caclculate the size of the data to be streamed in.
0
 
_ys_Commented:
From what I gather, you're trying to serialise an entire std::map into the stream as void*, and deserialise it on the other side into an std::map instance.

Only problem is ... is the entire map contiguous in memory ?

Wouldn't
mSTLString.insert(MAPSTRTOSTR::value_type("unity","is strength");
just insert two pointers to the strings directly into the memory space ?

My recommendation would be to pass a UDT back to the client. They're automatically marshalled (support added with DCOM 1.2).

I have seen std objects being passed around within COM. Just can't remember where or when.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.