Solved

Javascript: if child doesn't exist, don't try and close it.

Posted on 2003-11-04
5
596 Views
Last Modified: 2010-05-18
I am new to javascript so I am not sure how to word my code.

I have a perl script which comes back to the same html page more than once, but the child window isn't always open... and the code I have will try and close the window even if it doesn't exist. I need to check to see if the child window exists first.


Current code:

<SCRIPT LANGUAGE="JavaScript">

<!--

function body_OnLoad() {
  document.form_SleepChild.submit();
}

//-->
</SCRIPT>



Desired code:

<SCRIPT LANGUAGE="JavaScript">
<!--

function body_OnLoad()
{
         if(exist.childWindow_name)
         {
         document.form_SleepChild.submit();
         }
}

//-->
</SCRIPT>


Any help would be much appreciated.

Thank you :)
0
Comment
Question by:dr34m3rs
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5 Comments
 
LVL 25

Accepted Solution

by:
James Rodgers earned 125 total points
ID: 9680618
myWin=window.open('','','');

<SCRIPT LANGUAGE="JavaScript">
<!--

function body_OnLoad()
{
         if(myWin && !myWin.closed)
         {
         document.form_SleepChild.submit();
         }
}

//-->
</SCRIPT>

0
 
LVL 1

Author Comment

by:dr34m3rs
ID: 9680784
Ok that worked great Jester_48, so I will accept your answer.

I do get a javascript error icon on the very lower left corner of my IE browser though. Just curious if there is any way to keep this from happening?

Thank you for all your help :)
0
 
LVL 1

Author Comment

by:dr34m3rs
ID: 9680840
The error I get is wildchild undefined...
0
 
LVL 1

Author Comment

by:dr34m3rs
ID: 9680852
nevermind I solved it :)

Thanks.
0
 
LVL 25

Expert Comment

by:James Rodgers
ID: 9680998
thanks for the points
0

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