Putting ints into CStrings

How can i get my

int age

into this CString correctly. When the method is called like this cout << myClient.toString();
it prints funny characters instead of the the number stored in the int. How do i get it to "go in" correctly

CODE EXTRACT--------------------

CString Client::toString()
{
      CString retVal = "Name:\t"  + name + "\nAge\t:" + age + "\nSex:\t" + sex + "\nTelephone:\t" + telephone + '\n';
      return retVal;
}

Surely this is obvious to someone!!!

Thanks in advance!

Phill!
PhilluminatiAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

grg99Commented:
You're probably getting the right answer :)

You're saying: Pls Mr Compiler, take the address of where you're going to put the string "Name:\t", then add that to my variable "name",
then add a bunch more addresses and integers together too.

In classsic C, you'd probably do something like:  
retVal = malloc(200);
sprintf( retVal, "Name:\t:%d\nAge:\t:%d ..... ",   name, age, ... );

In C++ you probably wan t to wrap all the integer variables with some function that converts them to CStrings, then the "+" operator will be interpreted as the overloaded CString concat operator, and things will work a bit better.    Except you're returning a local variable, which is unlikely to work very well in the long run.  











0
efnCommented:
You may be able to use CString::Format.  It formats the string contents according to a format string like sprintf.  For example:

CString retval;
retval.Format( "Name:\t%s\nAge\t:%d\nSex:\t%c\nTelephone:\t%s\n", name, age, sex, telephone);

This only works if your data has types that sprintf knows.  You can put out a CString with a format specification of %s if you convert the corresponding argument.  For example, if name is a CString, you would match the %s with name.operator LPCTSTR().

Maybe I'm missing something, but I don't see any problem with returning a local variable by value.

--efn
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C++

From novice to tech pro — start learning today.