Fixing Decimal Points in Visual Basic

Hi,

I have some calculation in Visual Basic.  Variables are single type. I need to fix the decimal.(After decimal may be 3 digit). How can I round up ? If any body can assist me that would be great.

With thanks

Shakhawat
ShakhawatAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

monvelasquezCommented:
you can use the format function

FormattedVariable = Format(YourVariable, "0.000")
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
lttia1Commented:
how abt this:

FormattedVariable = Round(YourVariable, 3)
0
vkaushikCommented:
You can use the Format function to round up the expression. Following are some examples:

Dim MyStr As String

MyStr = Format(23)   ' Returns "23".

' User-defined numeric formats.
MyStr = Format(5459.4234, "##,##0.000")   ' Returns "5,459.423".
MyStr = Format(334.9723, "###0.000")   ' Returns "334.972".
0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

bhagyeshtCommented:
1. format function
or
2. convert to string and manuplate
0
LastToKnow0Commented:
You can round to the nearest thousandth (instead of always down) by adding 5/10000 to the number before rounding.

Ex:
Round( 0 + 0.0005, 3) 'returns 0
Round(0.0005 + 0.0005 , 3) 'returns 0.001
Round(0.00049 + 0.0005, 3) 'returns 0

Function RoundNearest(in as Single, precision as Integer) as Single
    RoundNearest=Round(in + .5 * 10 ^(-precision), precision)
End Function
0
bhagyeshtCommented:
Shakhawat: can we have some feedback?
0
vkaushikCommented:
Yes mate. We are awaiting the feedback.
0
ShakhawatAuthor Commented:
I already accepted one code and gave the point.

Shakhawat
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Game Programming

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.