p1800volvo
asked on
nawk regular expression issue
I have a bit of code in nawk that I would like some help with. It is searching a file for User Agent strings and giving me a count of each login by browser version. The problem is when I search on Netscape/7.1 it bombs out since the string has a / character. I have tried a leading \ with no help. Here is the code;
nawk '
found=0
/4.79/ { count6++;found=1 }
/Netscape/7.1/ {count7++;found=1 }
{ if(found == 0) countu++ }
END{
print "Netscape 4.79",count6
Print "Netscape 7.1", count7
print "Unknown",countu
}' > $1.uaout
What character should I use to make nawk ignore the / character in Netscape/7.1? Searching on 7.1 is not an option due to the number of records with this string as part of a the time field.
Thanks!
nawk '
found=0
/4.79/ { count6++;found=1 }
/Netscape/7.1/ {count7++;found=1 }
{ if(found == 0) countu++ }
END{
print "Netscape 4.79",count6
Print "Netscape 7.1", count7
print "Unknown",countu
}' > $1.uaout
What character should I use to make nawk ignore the / character in Netscape/7.1? Searching on 7.1 is not an option due to the number of records with this string as part of a the time field.
Thanks!
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ASKER
glassd has it! That did it. Thanks again!
Credit should also be given to rishisk for his answer since the "P" was a mistake that prevented it from completing in later steps.
Credit should also be given to rishisk for his answer since the "P" was a mistake that prevented it from completing in later steps.
Print "Netscape 7.1", count7
Change this to
print "Netscape 7.1", count7