Crystal Report formula - loop, condition

Tabel1: ReportID(PK), OrderID (one report only has one order)
Tabel2: OrderID, ItemID (no primary key)
Tabel3: ItemID(PK), Itemname  

I need a formula to print all the itemnames for a certain ReportID in one field, so this field can appear in report heading. Can anyone please help? Thanks.
jessica00Asked:
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peter57rCommented:
So is your report only reporting on one selected ReportID?

Pete
0
peter57rCommented:
Assuming you are only reporting one ReportID in a report.

Create a formula fDetail:

global stringvar vItemnames;
vItemnames := vItemnames & ", " & {ItemId.ItemName};

This goes into the detail line but can be suppressed.

Create a formuls fRH:

Whileprintingrecords;
global stringvar vItemnames;
vItemnames

This goes into the report header and needs to be formatted as 'Can Grow'.


Pete

0
jessica00Author Commented:
Yes, one selected ReportID.
I tried your suggestion, and get duplicated itemnames, and my other report details become duplicated as well.
 
Forgot to say, my report has two group sections. I have another two tables to hold printed details.
Table 4: Group1_name(PK), ReportID
Table 5: Group2_name, Group1_name - no PK in this table

Any more hints you can give me? Thanks
0
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peter57rCommented:
'get duplicated itemnames, and my other report details become duplicated as well

I can sort out the duplicated itemnames but I don't know what you mean by 'other report details'.
Nothing I am doing is affecting the rest of the report.

Pete

The formula to go into the detail line is:

global stringvar array itemnames1;
global numbervar x;
numbervar y;
numbervar z;
z:=0;
for y:=1 to x do
(
if itemnames1[y] = {ItemId.ItemName} then
(
z:=1
)
else
// do nothing
(
y:=y
);
);

if z=0 then
(x:=x+1;
redim preserve itemnames1[x];
itemnames1[x]:= {ItemId.ItemName};
0
)
else
(
x:=x;
0
);



The formula to go into the Report Header is :
whileprintingrecords;
global stringvar array itemnames1;
global numbervar x;
local stringvar result;
local numbervar xx;

result:= itemnames1[1];
for xx:=2 to x do
result:= result & chr(13) & itemnames1[xx];

result



0
jessica00Author Commented:
I sorted out with a subreport
0
moduloCommented:
PAQed, with points refunded (250)

modulo
Community Support Moderator
0

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