How to make a list of xth latest files in a dir and sub-dir?

I'm looking for a script that will search through a dir and its subdirs and return in a list (html file),  the 10 or 20 most recent files, according to last modified timestamp (regardless of file type). Preferably the list will have a link to each of the files (the dir is a sub dir of my htdocs folder). I'm running Apache 2.0.48 on Win XpPro and have perl 5.6.1 installed. No real experience with perl so don't get too techie on me!!! ;-)

Thanks Robin
irlrobinsAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

ozoCommented:
use CGI qw/:standard/;
use File::Find;
@dirstosearch=("/path/to/dir");
find( sub{push@list,[-M,$File::Find::name] }, @dirstosearch);
print header,start_html("list of 20 latest files")
for( (sort $a->[0]<=>$b->[0],@list)[0..19] ){
    print qq(<a href="http://mysite.com/$_->[1]">$_->[1]</a><br>);
}
print end_html;
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
irlrobinsAuthor Commented:
Thanks ozo. I'll try it out tomorrow and if it works the points are yours!
0
irlrobinsAuthor Commented:
Ok I tried that and i get the a Server 500 error. Here's whats in the error logs:
[Fri Nov 07 12:09:30 2003] [error] [client xxxx] Premature end of script headers: list.cgi
[Fri Nov 07 12:09:30 2003] [error] [client xxxx] syntax error at C:/Program Files/Apache Group/Apache2/cgi-bin/list.cgi line 8, near "){"
[Fri Nov 07 12:09:30 2003] [error] [client xxxx] Execution of C:/Program Files/Apache Group/Apache2/cgi-bin/list.cgi aborted due to compilation errors.

Line 8 is "for( (sort $a->[0]<=>$b->[0],@list)[0..19] ){"

Whats the prob?

Thanks again
0
irlrobinsAuthor Commented:
Ok i added a ';' to the end of line 7 "print header,start_html("list of 20 latest files")"

Script now runs and returns a list of 20 files. But they're not the most recent ones. In fact I've no idea why it picks the files that it does....
0
irlrobinsAuthor Commented:
ok I've fixed it. I've changed the ozo's solution slightly:

a) to fix his errors (haven't you heard of testing?? ;-) )
b) it now only lists files that end in .txt and .jpg and no directories), Also using substr so i can formulate a proper url (it was adding extra dir's to the path)

Anyway Ozo's points are yours. Thanks for your help. Appreciate it. (solution follows)

#!/usr/bin/perl -w

use CGI qw/:standard/;
use File::Find;

@dirstosearch=("../htdocs/access/");
find ( sub  
      {
      if ((!-d)&&((/\.txt$/)||(/\.jpg$/))) #will not push dir's or files that don't end with txt or jpg to the array
      {
      push@list,[-M,$File::Find::name]
      }
      }, @dirstosearch);
print header,start_html("The 20 most Recent Files");
for( (sort {$a->[0]<=>$b->[0]}@list)[0..19] ){
  $substring1=substr($_->[1],9); #substring to from correct url
  $substring2=substr($_->[1],19); #substring to form visible link in correct format
  print qq(<a href="http://mysite.ie$substring1">$substring2</a><br>);
}
print end_html;
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Scripting Languages

From novice to tech pro — start learning today.