Link to home
Start Free TrialLog in
Avatar of PSERK
PSERK

asked on

Graphical problem

Hello programmers!
I have a picture:
http://www.hot.ee/serk/pilt2.jpg

Does anybody have any ideas or examples, how to scan in the time that there is(upper part of the circle)

I can do everything else I need with this picture but i don't understand How I can scan in the time that is there(24, 23, 22, 21, 20, 19, 18, 17 and so on)
If anybody can help with examples or just WITH GOOD IDEAS THEN PLEASE LET ME KNOW!!!

Thank you!!
Priit Serk
serk@hot.ee
Avatar of geobul
geobul

Hi,

I think you need an OCR component. And I have no experience using OCR.

Regards, Geo
Hello,

   Well.....I do not know ...but interesting picture anyway :))
This looks like a "Photo" of some sort of rotating timer (or clock) display disk, if you are getting an Image from a digital camera that takes a photo of this disk, you might have a very very difficult time, because you may not be able to get an exact position for what you want scan, , , , but if you are only accesssing a single Digital Bitmap, then you might be able to presicly navagate this bitmap and compare the pixels to the same bitmap where you know the exact location of the pixels for the time numbers to compare
Avatar of PSERK

ASKER

That kind of picture comes from the trucks. All their driving data is saved to that kind of image. I managed successfully to convert the picture to pf1bit image. So there are now only black and white pixels. I had much trouble with finding the center point of the image, because it is not correct circle. It seems to be but it is not. There are 4 different types of images but their size is almost/practically same, only difffer in some pixels. So at this point I am trying to scan in the time using certain radius. I don't know if this works fine but I'll let you know as soon as possible. But I must go and do my school homework

ASKER CERTIFIED SOLUTION
Avatar of Povilas
Povilas

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial