• C

performing a function on all files in a drectory

i've got an api that takes in either a file name or a directory name and calls a function.  i use GetFileAttributes to find out if what is passed in is a file or directory.  for a file i just pass it on to the function, but if a directory is passed, i need to write something that will recursively pass each file from that directory to my funtion until all files have been preoccessed.  i need a code example for a little help since i've been coding in VB for the past few months, my C programming is really rusty.  i was thinking i'd need to use findfirstfile and findnextfile somewhere.  thanks for the help

Kris
kris-maycoAsked:
Who is Participating?
 
Kent OlsenData Warehouse Architect / DBACommented:

findfirst() is not recursive so when you're scanning a directory's contents, call it on a subdirectory voids the ability to scan the rest of the parent directory.

In "metacode", here's what the function to recursively scan all subdirectories will look like:


ScanDirectory (char *BasePath)
{
  char **Subdirs;    /* Table of subdirectories  */
  int   SubdirCount = 0;
  int   idx;
  char *path;

  path = findfirst (BasePath);
  while (path)
  {
    if (isdirectory (path))
    {
      Subdirs = AddPathToTable (Subdirs, SubdirCount, path);
      SubdirCount++;
    }
    else
      ProcessFile (path);
    path = findnext ();
  }

//  Now process all of the subdirs
  for (idx = 0; idx < SubdirCount; SubdirCount++)
  {
    path = BuildPathName (Subdirs[idx]);
    ScanDirecotry (path);
  }
}


Good Luck!
Kent
0
 
bobbit31Commented:
yes, use ResultSetMetaData Class:

ResultSetMetaData rsmd = rs.getMetaData();
System.out.println(rsmd.getColumnDisplaySize(<int column>));
0
 
bobbit31Commented:
oops, sorry, my comment above was obviously posted in the wrong thread ;)
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.