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Keeping a number as a lenth=4 string

Posted on 2003-11-07
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Last Modified: 2010-05-03
I have a string called CustomerID and I need it in the format 0003, 0014 etc...  this is what I have, but my problem is if I enter a number say 13 it gives me 00013 when I really want 0013.  It is the select case part of the function that the problem lays I think.

'Creates a new JobID
Public Function NewJobID() As String
    Dim JobID As String, Counter As Single
    JobID = LastJobID + 1
    LastJobID = LastJobID + 1
    Call UpdateLastIDs
    Select Case JobID
        Case 1 To 9
            NewJobID = "000" & JobID
        Case 10 To 99
            NewJobID = "00" & JobID
        Case 100 To 999
            NewJobID = "0" & JobID
        Case 1000 To 9999
            NewJobID = JobID
    End Select
End Function


Thanks, Jebus
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Question by:dj__jebus
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3 Comments
 

Author Comment

by:dj__jebus
ID: 9706198
lol, woops I said CustomerID    oh well, I have identical functions for both CustomerID and JobID, same thing...
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Accepted Solution

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NBrownoh earned 50 total points
ID: 9706222
Ret = Abs(4 - Len(CStr(YourNum)))
FormatNum = String(Ret, "0") & YourNum

FormatNum is the number correctly formatted for this, and YourNum should be replaced with the variable holding the number you want to format
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LVL 3

Expert Comment

by:NBrownoh
ID: 9706227
BTW FormatNum is a string variable and Ret is an integer variable
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