Solved

Brain breaking: Diamond price.

Posted on 2003-11-09
12
319 Views
Last Modified: 2006-11-17
A diamon's price is ratio to square of its mass(not sure if it true in reality). If the diamon was cut to 3 smaller diamonds  the ratio remain the same. Is the owner got more money or less , if he sold the diamond as a big one or cut it to three smaller ones?If it it true, that he will lost money if cut the diamond by three smaller one, in which case, the money lost it most?
A little suggestion: In my opinion, it is a lot easier for one to read and understand other's solutions if all of us use same variables refer to the same problem. So if  you thing my suggestion is not violate your "free of choice" please use the following:

Let M be the mass of the big diamond, and a, b and c be the masses of the 3 smallers one after cut.
Let P be the price of M and x,y,z be prices of a, b, c respectively.
Then what was given is:
                  P/M^2 = x/a^2 = y/b^2 = z/c^2
find if:         P > x + y + z   *
and if *  is true, find  Max(P - (x + y + z) )  
Please have fun.
0
Comment
Question by:vnhenry
12 Comments
 
LVL 5

Expert Comment

by:arjanh
ID: 9709407
A simple example shows that splitting is a bad choice:
If M=9 and a=3, b=3, c=3 and if we assume the constant P/M^2 to be 1, then P=81 and x=y=z=9 and 81 > 27.

Changing to a=4 and b=2, results in x=16 and y=4. So the increase of a leads to a bigger increase of x (+7) than the decrease of y (-5) caused by the decrease of b.

Hence the price difference is maximized when a=b=c. Because of the squaring, every little increase of one of the weights leads to a bigger increase in price than the decrease in price of the diamond that becomes smaller.

I tried to prove it with the formulas, but I'm stuck at proving that the Max(ab+ac+bc) with M=a+b+c is at a=b=c...
0
 
LVL 22

Expert Comment

by:grg99
ID: 9710004
If I understand correctly the question is:

is( m squared) more than 3 times ((m/3) squared)?

By my old algebra I get:

m squared minus three (m/3) squared = 2/3 m squared

That means m squared will always exceed the other by a factor of 2/3 m squared.


0
 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9710155
Lagrange multipliers gives me split it into 3 for the max loss but I think there is probably a prettier way of doing this.

The problem reduces to finding (if E is the price difference)

  Max E =  M² -(a² + b² + c²)

subject to a + b + c = M.  Equivalently as a Lagrange multiplier this is

 Max E =  M² -(a² + b² + c²) + L(M-a-b-c)

the Max/Mins are given by dE/da = dE/db = dE/db = dE/dL =0

ie -2a-L=0   -2b-L=0  -2c-L=0  M-a-b-c=0

these have solution a=b=c=M/3  L=-2M/3 (clearly this function only has  1 turning point and is a Max)

Hence worsst split is a=b=c=M/3

As I said there is probably a prettier way and I will look later.

GfW
0
U.S. Department of Agriculture and Acronis Access

With the new era of mobile computing, smartphones and tablets, wireless communications and cloud services, the USDA sought to take advantage of a mobilized workforce and the blurring lines between personal and corporate computing resources.

 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9710177
Sorry E is the price difference  divided by the constant of propotionality to be precise
0
 
LVL 15

Expert Comment

by:JakobA
ID: 9710185
look at squares:
if        a^2  =  b
then   (a+1)^2  =  b +(2a+1)
and    (a-1)^2   =  b  -(2a-1)

thus increasing the size of a diamond will allways give more 'gain' than an equal reduction of the size of an same-sized or smaller diamond will give 'loss'.

re "not sure if it true in reality"  >  not true, if it were the profession of 'diamondcutter' would not exist.
partly true in the early stages of gathering where the whethered matte surface of the raw diamonds make it hard to inspect then for color and other 'wonderfull flaws' :-))

regards JakobA
0
 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9710249
This is a bit prettier. To maximise E

 E  =  M² - (a² + b² + c²)

   = -2M²/3 -( a² + b² + c²) + 2M² - M²/3
 
   = 2M²/3 - (a² + b² + c²) + 2M(a + b + c) - 3M²/9

   = 2M²/3 - (a-M/3)²- (b-M/3)² - (c-M/3)²


Max clearly occuring at a = b= c= m/3
0
 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9710315
something wrong in the steps there should end up as

E  =  M² - (a² + b² + c²)

    = M²/3 - (a-M/3)² - (b-M/3)² - (c-M/3)²

Max  occuring at     a =  b =  c =  M/3
0
 
LVL 31

Accepted Solution

by:
GwynforWeb earned 100 total points
ID: 9710407
This is it (phew!)

E = (a+b+c)² - (a² + b² + c²)

  = M² - (a² + b² + c²)

  = 2M²/3 -(a² + b² + c²) + M²/3

  = 2M²/3 - (a² + b² + c²) + 2M²/3 - M²/3

  = 2M²/3 - (a² + b² + c²) + 2M/3(a + b + c) - 3M²/9

  = 2M²/3 - (a-M/3)²- (b-M/3)² - (c-M/3)²

with Max of  2M²/3  occuring at  a = b = c = M/3

0
 

Author Comment

by:vnhenry
ID: 9712024
Hi all
thank for participating
I dont get why you have E = M^2 - (a^2+b^2+c^2)While  M and a, b, c are masses(unit karat in diamond business, may be called  ounce in science) and  E, unit should be dollars ($) Please read the post again. And please show all the steps
I dont know why you all ignore the variable P (which is the value of the diamond before cut).
By the way how do you write the square sign like that( not a^2).  Did you write from a word document then paste into this?Or can you write directly
To JacobA. And it should be the variable use to compute the money lost too.
I think it true, JacobA. I just remember the story "It good to be Michel Duglas and Catherin Zethazon (something like that : ))) he bought for her 10 karats diamond for they weeding for $200,000 , I knew that a 2karats_diamond now cost about $5,000. So the bigger the rock, the more valueble it get???
 
0
 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9712135
Sorry my I should have been more explicit in my analysis I was working in non-dimensional values. ( I get the a² etc by cutting and pasting from a notepad file with the ASCII  set in it which I keep handy, I have not found a key baord method for a text area. I posted that set earlier today for all to use)

Since price is  k*mass² then price of large diamond is P =  kM² = k(a+b+c)² and the prices of the smaller are  ka², kb², and kc² then the problem is to find

  Max E = kM² - (ka² + kb² +  kc²)

which is equivalent to finding (since k is +ve)

 Max ( M² - (a² + b² +  c²) )

which I have show above   (using M=a + b +c )

Max ( M² - (a² + b² +  c²) ) = Max ( 2M²/3 - (a-M/3)² - (b-M/3)² - (c-M/3)² )

and clearly occurs at a = b = c = M/3

price of large P = kM²

price othe 3 smaller diamonds at weight  M/3 each is  

        3*k(M/3)² = kM²/3 = P/3

hence the difference is   P - P/3 = 2P/3

 
0
 
LVL 31

Expert Comment

by:GwynforWeb
ID: 9712152
If you do not like me dropping the k then we can do like this as well ( using M=a + b +c )

  Max E = kM² - (ka² + kb² +  kc²)

           = k( M² - (a² + b² +  c²) )

           = k( 2M²/3 - (a-M/3)² - (b-M/3)² - (c-M/3)² )

Max occuring at   a = b = c = M/3

with max being    2kM²/3  = 2P/3

           
0
 

Author Comment

by:vnhenry
ID: 9739666
You got it.
However, in my work, the different between P and (x+Y=y+z)
is: P - (x+y+z)= 2P(ab+bc+ca)/M^2.
I did not see any wrong in your work.  So you got the points
0

Featured Post

Enterprise Mobility and BYOD For Dummies

Like “For Dummies” books, you can read this in whatever order you choose and learn about mobility and BYOD; and how to put a competitive mobile infrastructure in place. Developed for SMBs and large enterprises alike, you will find helpful use cases, planning, and implementation.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Baseline sigma 8 37
Simplify expression 3 99
What statistical method/formula can be used for Range and Trend? 4 85
ANOVA 3 8
This article seeks to propel the full implementation of geothermal power plants in Mexico as a renewable energy source.
Article by: Nicole
This is a research brief on the potential colonization of humans on Mars.
This is a video describing the growing solar energy use in Utah. This is a topic that greatly interests me and so I decided to produce a video about it.
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…

831 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question