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# Help with arrays of pointers to functions!!!

Posted on 2003-11-09
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Hello all!  I have been working on this work a few days now and can't seem to get the exact answer I am looking for.  Maybe someone here can help me out.  What I am trying to do is this: I am trying to get all the pointers to have the same type.  The pointers must be to functions of the same return type that receive arguments of the same type. The minimum and maximum functions  print only the minimum and maximum and don't return anything.  The average should return nothingand take the same parameters as printArray, minimum, and maximum.  The pointers of the four functions should be stored in array processGrades and use the choice made by the user as teh subscript into the array for calling each function.  Please HELP me!! Thank you.
Here is my code so far:

#include <iostream>

using std::fixed;
using std::endl;
using std::cout;
using std::left;
using std::cin;

#include <iomanip>

using std::setw;
using std::setprecision;

const int students = 3;
const int exams = 4;

void minimum (int [] [exams], int, int);
void maximum (int [] [exams], int, int);
double average (int [], int);
void printArray (int [] [exams], int, int);

int main()
{
int choice = 0;
{{77, 68, 86, 73},
{96, 87, 89, 78},
{70, 90, 86, 81}};
while (choice != 4){
cout << "\nEnter a choice:" << endl;
cout << " 0  Print the array of grades" << endl;
cout << " 1  Find the minimum grade" << endl;
cout << " 2  Find the maximim grade" << endl;
cout << " 3  Print the average on all tests for each student" << endl;
cout << " 4  End program" << endl;
cout << "? ";
cin >> choice;

if (choice == 4) break;
if (choice == 0){
cout << "The is ";
if (choice == 1){
cout << "\n\tThe lowest grade is ";
if (choice == 2){
cout << "\n\tThe highest grade is ";
if (choice == 3){
cout << fixed << setprecision(2);
for (int person = 0; person < students; person++)
cout << "\n\tThe average for student " << person << " is ";
}
return 0;
}

void minimum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < tests; j++)
}
void maximum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < pupils; j++)
}

double average (int setOfGrades[], int tests)
{
int total = 0;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;

}

void printArray (int grades[] [exams], int pupils, int tests)
{
cout << left << "            [0]  [1]  [2]  [3]";

for (int i = 0; i < pupils; i++){
cout << "\nstudentGrades[" << i << "]";

for (int j = 0; i < tests; j++)
}
}
0
Question by:marcypark
• 16
• 10
• 8
• +1

LVL 10

Expert Comment

ID: 9712271
Declare an array of pointers something like

The above declaration says that procesGrades is an array (of size 4) of pointers to functions which return void and take 3 parameters - a 2-dimensional int array, int, int

Now, before your while loop, let the array locations point to your functions by saying

Altenatively, you can also use the following statements to do the same

Now in your while loop, after accepting the user's choice, just call the respctive function in the respcetive array locations as below

0

LVL 15

Expert Comment

ID: 9712479
Sys_Prog gave you most of the answer.

The declaration of the grades parameter in this shouldn't compile.  It should be

You will also, of course, have to change the average function so it matches the others.

--efn
0

LVL 10

Expert Comment

ID: 9712501
Hi efn

My Function Pointer declaration does compile

Actually what u said is related to while declaring a function with multi-dimension array argument

When u are passing multi-dimension araay, u can omit the size of ONLY THE FIRST dimension. the size of rest all dimensions need to be given

But this is NOT TRUE when u are declaring a pointer to that function. Your function pointer need not mention the size of any of the array dimensions.

0

LVL 15

Expert Comment

ID: 9712768
Hi Sys_Prog,

I couldn't find a definitive ruling on this in the standard, but Microsoft Visual C++ 6.0, Borland C++Builder 4, and gcc 3.2 all rejected the line.

VC++:

error C2087: '<Unknown>' : missing subscript

BCB:

E2453 Size of the type 'int[]' is unknown or zero.

gcc:

declaration of `grades' as multidimensional array must have bounds

The message from gcc appeared to be labeled as a warning, but was severe enough to keep the program from linking.  This was with dev-c++.

So what compiler do you use that compiles this?

--efn
0

LVL 10

Expert Comment

ID: 9712783
I am using a GNU compiler  -  mingw32 and it works fine with this

0

LVL 15

Expert Comment

ID: 9712806
So I guess what we can say to marcypark is:  If your compiler complains about the function pointer array declaration, try specifying the second array bound.

--efn
0

LVL 10

Expert Comment

ID: 9712817
Yes, I guess that would be a better option

Amit
0

LVL 30

Expert Comment

ID: 9714024
Sys_Prog,

I'm not sure how you were able to compile that since in addition, it also has an extra variable name that doesn't belong there.

void ( * processGrades[4] ) (int grades[][], int, int ) ; //This should not compile

void ( * processGrades[4] ) (int [][exams], int, int ) ; // This is good

You can declare and initialize it at the same time via following method:

void ( * processGrades[4] ) (int [][exams], int, int ) = {minimum, maximum, printArray} ;

Before you can use the average function in this declaration, you need to change the return type and the arguments to match that of the other functions.

0

LVL 30

Expert Comment

ID: 9714056
Niether of the following two lines will compile on VC++ 7.1

void ( * processGrades[4] ) (int grades[][], int, int ) ; //This should not compile
void ( * processGrades[4] ) (int [][], int, int ) ; //This should not compile

The VC++ 7.1 compiler is considered more compliant to the C++ standard then the GNU 3.2.x compiler.

>>But this is NOT TRUE when u are declaring a pointer to that function. Your function pointer need not mention the size of any of
>>the array dimensions.

Can you reffer to the part of the standard that specifically states that this is allowed?
0

LVL 10

Expert Comment

ID: 9714082
Hi Axter,

I have tried the same with gnu and VC 6.0 and did not face any problem

--Amit
0

LVL 30

Expert Comment

ID: 9714123
Can you post exactly what you have tried?

Please copy and paste the code, so we can be sure we're talking about the same thing.
0

LVL 30

Expert Comment

ID: 9714204
Simple test:

int main(int, char**)
{
void ( * processGrades[4] ) (int grades[][], int, int ) = {minimum, maximum, printArray} ;
return 0;
}

The above code does not compile on any C++ compliant compiler that I'm aware of.

I just tried to compile it on VC++ 6.0 and, it fails.

I also used Dev-C++ which uses the same compiler that mingw32 uses, and it also fails to compile.

I don't think you're testing the exact same code.
0

LVL 30

Expert Comment

ID: 9714220
FYI:
I'm not implying that VC++ 6.0 is a compliant C++ compiler.

On the other hand, VC++ 7.1 is considered to be a very good C++ compliant compilers.
0

LVL 10

Expert Comment

ID: 9714229
I tried again on Dev C++, and it does compile at my installation

--Amit

0

LVL 10

Expert Comment

ID: 9714234
Thanks for the info regarding compliance of VC 6 and VC 7 to C++.

We can may be try on some UNIX based compiler, but it works with GNU compiler

-- Amit
0

LVL 30

Expert Comment

ID: 9714264
Again,
Please post the EXACT code you're using for testing, so we can be sure we're talking about the same thing.
0

LVL 30

Expert Comment

ID: 9714287

7.0 is also not a very good C++ compliant compiler.  It's better then 6.0, but it still has too many compliance issues.

With 7.1 Microsoft finally got it right.
0

LVL 10

Expert Comment

ID: 9714308
Hi Axter,

I am testing exactly the same code what u tried.

Only thing is that I corrected the signature for average in the questioner's code.

--Amit

0

Author Comment

ID: 9718565
Ok, I tried to make the average function look like the other functions (maximum and minimum), but the compliler complains.  Also, I tried to insert the array of the students grades but only got 16 errors.  Can you please help me out a little more?  I am using Visual Basic 6.0 C++ in case you are wondering:

#include <iostream>

using std::fixed;
using std::endl;
using std::cout;
using std::left;
using std::cin;

#include <iomanip>

using std::setw;
using std::setprecision;

const int students = 3;
const int exams = 4;

void minimum (int [] [exams], int, int);
void maximum (int [] [exams], int, int);
void average (int [] [exams], int, int);
void printArray (int [] [exams], int, int);

int main()
{
int choice = 0;
{{77, 68, 86, 73},
{96, 87, 89, 78},
{70, 90, 86, 81}};
while (choice != 4){
cout << "\nEnter a choice:" << endl;
cout << " 0  Print the array of grades" << endl;
cout << " 1  Find the minimum grade" << endl;
cout << " 2  Find the maximim grade" << endl;
cout << " 3  Print the average on all tests for each student" << endl;
cout << " 4  End program" << endl;
cout << "? ";
cin >> choice;

if (choice == 4) break;
if (choice == 0){
cout << "The is ";
if (choice == 1){
cout << "\n\tThe lowest grade is ";
if (choice == 2){
cout << "\n\tThe highest grade is ";
if (choice == 3){
cout << fixed << setprecision(2);
for (int person = 0; person < students; person++)
cout << "\n\tThe average for student " << person << " is ";
}
return 0;
}

void minimum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < tests; j++)
}
void maximum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < pupils; j++)
}

void average (int setOfGrades[], int tests)
{
int total = 0;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;

}

void printArray (int grades[] [exams], int pupils, int tests)
{
cout << left << "            [0]  [1]  [2]  [3]";

for (int i = 0; i < pupils; i++){
cout << "\nstudentGrades[" << i << "]";

for (int j = 0; i < tests; j++)
}
}
0

Author Comment

ID: 9718886
Can anyone help me?
0

LVL 15

Expert Comment

ID: 9718891
I tried this in Visual C++ 6.0 (no Basic) and it compiled fine.  Only the linker complained because there was no average function that matched the declaration.  You have to change the average function itself as well as the declaration you have already changed.

--efn
0

Author Comment

ID: 9719173
What could I change it to?
0

LVL 15

Expert Comment

ID: 9719206
The way you have already declared it, the same as the other functions:

void average (int [] [exams], int, int);

One of the integer parameters can tell the function how many tests there are.  The other one can tell the function which student to use, rather than how many students there are as in the other functions.  If you make this design change, you will also have to change the call to the average function correspondingly.

--efn
0

Author Comment

ID: 9719232
I am sooo lost.  Here is the code that I have changed.  What am I still doing wrong?

#include <iostream>

using std::fixed;
using std::endl;
using std::cout;
using std::left;
using std::cin;

#include <iomanip>

using std::setw;
using std::setprecision;

const int students = 3;
const int exams = 4;

void minimum (int [] [exams], int, int);
void maximum (int [] [exams], int, int);
void average (int [] [exams], int, int);
void printArray (int [] [exams], int, int);

int main()
{
int choice = 0;
{{77, 68, 86, 73},
{96, 87, 89, 78},
{70, 90, 86, 81}};
while (choice != 4){
cout << "\nEnter a choice:" << endl;
cout << " 0  Print the array of grades" << endl;
cout << " 1  Find the minimum grade" << endl;
cout << " 2  Find the maximim grade" << endl;
cout << " 3  Print the average on all tests for each student" << endl;
cout << " 4  End program" << endl;
cout << "? ";
cin >> choice;

if (choice == 4) break;
if (choice == 0){
cout << "The is ";
if (choice == 1){
cout << "\n\tThe lowest grade is ";
if (choice == 2){
cout << "\n\tThe highest grade is ";
if (choice == 3){
cout << fixed << setprecision(2);
for (int person = 0; person < students; person++)
cout << "\n\tThe average for student " << person << " is ";
}
return 0;
}

void minimum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < tests; j++)
}
void maximum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < pupils; j++)
}

void average (int [] [exams], int, int)
{
int total = 0;
int tests;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;

}

void printArray (int grades[] [exams], int pupils, int tests)
{
cout << left << "            [0]  [1]  [2]  [3]";

for (int i = 0; i < pupils; i++){
cout << "\nstudentGrades[" << i << "]";

for (int j = 0; i < tests; j++)
}
}
0

LVL 30

Expert Comment

ID: 9719313
What did you change?

Exactly what did you change, and why do you feel something is wrong?
0

LVL 30

Expert Comment

ID: 9719319
>>I am testing exactly the same code what u tried.
>>Only thing is that I corrected the signature for average in the questioner's code.

Then it's not exactly the same.
You can't be testing the same thing that we're testing, because it fails to compile on VC++ 6.0 and on the GNU compiler.
So you have to be testing some thing different from what we're testing.

Don't be shy.... Post you got.
0

Author Comment

ID: 9719326
I changed the average function to void and tried to make it like the others.  There is something wrong because the error reads: error C2109: subscript requires array or pointer type right at the average function.
0

Author Comment

ID: 9719339
The code that I am testing is the code that I posted up last.
0

LVL 30

Expert Comment

ID: 9719357
What line is giving you the compile error?
0

Author Comment

ID: 9719370

0

LVL 30

Expert Comment

ID: 9719388
Try changing your average function to the following:

void average (int setOfGrades[] [exams], int index, int tests)
{
int total = 0;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;
}
0

LVL 30

Expert Comment

ID: 9719393
And change the code calling average to the following:

for (int person = 0; person < students; person++)
cout << "\n\tThe average for student " << person << " is ";
0

Author Comment

ID: 9719410
The program runs, but when I choose option 0, to print the array, the program goes crazy and ends up with a message to send the error report to Mircosoft.  Also, with option 3, the average, it does not print the average for each student.  For student0 is shows nothing, for student1 it shows nothing and for student2 it shows 1399667.25?  What is going on here?  BTW, thank you for sticking with me!
0

LVL 30

Expert Comment

ID: 9719442
The last for-loop is using i instead of j in your printArray function
0

LVL 30

Expert Comment

ID: 9719447
Here's the correction:

void printArray (int grades[] [exams], int pupils, int tests)
{
cout << left << "            [0]  [1]  [2]  [3]";

for (int i = 0; i < pupils; ++i)
{
cout << "\nstudentGrades[" << i << "]";

for (int j = 0; j < tests; ++j)
}
}
0

Author Comment

ID: 9719449
Ok, the last question.  Why won't the program print the correct average for each student?
0

LVL 30

Expert Comment

ID: 9719481
Try the following for average:

void average (int grades[][exams], int pupils, int tests)
{
cout << fixed << setprecision(2);
for (int person = 0; person < pupils; person++)
{
cout << "\n\tThe average for student " << person << " is ";
int total = 0;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;
}
}

Then you can declare your function pointer via the following method:
void ( * processGrades[4] ) (int [][exams], int, int ) = {printArray, minimum, maximum, average} ;

You can then call it like this:
if (choice == 4) break;

0

LVL 30

Accepted Solution

Axter earned 500 total points
ID: 9719487
Full example:
const int students = 3;
const int exams = 4;

void minimum (int [] [exams], int, int);
void maximum (int [] [exams], int, int);
void average (int [] [exams], int, int);
void printArray (int [] [exams], int, int);

int main()
{
int choice = 0;
{{77, 68, 86, 73},
{96, 87, 89, 78},
{70, 90, 86, 81}};
void ( * processGrades[4] ) (int [][exams], int, int ) = {printArray, minimum, maximum, average} ;

while (choice != 4){
cout << "\nEnter a choice:" << endl;
cout << " 0  Print the array of grades" << endl;
cout << " 1  Find the minimum grade" << endl;
cout << " 2  Find the maximim grade" << endl;
cout << " 3  Print the average on all tests for each student" << endl;
cout << " 4  End program" << endl;
cout << "? ";
cin >> choice;

if (choice == 4) break;
}
return 0;
}

void minimum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < tests; j++)
}
void maximum (int grades[][exams], int pupils, int tests)
{
for (int i = 0; i < pupils; i++)
for (int j = 0; j < pupils; j++)
}

void average (int grades[][exams], int pupils, int tests)
{
cout << fixed << setprecision(2);
for (int person = 0; person < pupils; person++)
{
cout << "\n\tThe average for student " << person << " is ";
int total = 0;
for (int i = 0; i < tests; i++)
cout << static_cast<double>(total) / tests << endl;
}
}

void printArray (int grades[] [exams], int pupils, int tests)
{
cout << left << "            [0]  [1]  [2]  [3]";

for (int i = 0; i < pupils; ++i)
{
cout << "\nstudentGrades[" << i << "]";

for (int j = 0; j < tests; ++j)
}
}
0

Author Comment

ID: 9719531
Thank you very much!!!
0

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