Get fullpath of script

Hi!

Does anyone know, how to get the full-path of the directory of the perl-script!

This should work from ksh and bash!
my workaround:
---cut---
my $fullpath;

if ( $0=~/(^\/.*?)[^\/]*$/ ){
  #if called with fullpath or if script is in a ENV{PATH}-directory
  $fullpath=$1;
}else{
  $0=~/(.*?)[^\/]*$/;
  $fullpath=$ENV{PWD}."/".$1;
}
---cut---

but I guess, there must be a more simple solution!!!

thx
michi
LVL 1
wittyAsked:
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FishMongerCommented:
Use Cwd;

$cwd = cwd();
$fullpath = $cwd/$0;
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FishMongerCommented:
$fullpath = $cwd/$0;

I forgot the quotes; it should read

$fullpath = "$cwd/$0";  # unix
$fullpath = "$cwd\$0";  # windows
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jmcgOwnerCommented:
Actually, it is not always possible to discover the pathname of the script.

You have to start with $0, that's certain.

If $0 contains a / it is most likely a path relative to the current working directory -- but it may contain .. which will make simple concatenation yield a messy-looking path. There's help for this:

use Cwd qw(abs_path);

$fullpath = abs_path( $0) unless $0 =~ m{/};

Otherwise, you have to see if the name given in $0 appears as a directory entry in one of the elements of $ENV{PATH}.

@dirs = split /:/, $ENV{PATH};
my $path_found;
for (@dirs) {
     do { $path_found = $_/$0; last; } if -x $_/$0 ;
     }

and that, too, may need to be reformed:

$fullpath = abs_path($path_found);

Putting all of that together....

use Cwd qw(abs_path);

our $fullpath;
my $path_found;
if( $0 =~ m{/} ) {
     $path_found = $0;
   } else {
     for (split /:/, $ENV{PATH}) {
          do { $path_found = $_/$0; last } if -x $_/$0;
         }
    }

if ( $path_found ) {
   $full_path = abs_path( $path_found);
   } else {
   warn "could not locate full pathname for script $0";
   }

That will cover most possibilities, but it's still possible to execute something along a path that contains a directory you cannot read, which is one of the ways for it to be impossible to discover the proper name of the script.

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TintinCommented:
In almost all cases, the following will work:

#/usr/bin/perl
use FindBin qw($Bin $RealBin);

print "The directory this script lives in is $Bin\n";
print "The directory this script lives in with any links resolved is $RealBin\n";
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jmcgOwnerCommented:
Agreed. I second the suggestion to use FindBin (now a standard part of Perl).

 I looked at the source for FindBin and recognized all the portability considerations that it contains that my offering did not. The underlying method is identical, though, so I was on the right track.

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pjedmondCommented:
#!/usr/bin/perl

print `pwd`;


Using the shell command pwd? Works on older versions of Perl as well:)
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wittyAuthor Commented:
pwd doesn't have to be the script's directory!!!

you can call the perl-script with:

from everywhere:
/home/user/perl/script.pl

from "/home/user/x/y/":
../../perl/script.pl

from "/home/user/perl/"
script.pl
or
./script.pl

an if "/home/user/perl/" is included in $PATH:
from everywhere:
script.pl

michi
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jmcgOwnerCommented:
Yes, what you say is quite true. Some of the offered answers have not taken that into account. But the code I offered and the code in the FindBin module do take it into account and should give you the answer you asked for.
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pjedmondCommented:
oOOOOOPPPSSSS..... - was just offering my thoughts - and it looks like they weren't exactly worth the 2p offered :)
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