witty
asked on
Get fullpath of script
Hi!
Does anyone know, how to get the full-path of the directory of the perl-script!
This should work from ksh and bash!
my workaround:
---cut---
my $fullpath;
if ( $0=~/(^\/.*?)[^\/]*$/ ){
#if called with fullpath or if script is in a ENV{PATH}-directory
$fullpath=$1;
}else{
$0=~/(.*?)[^\/]*$/;
$fullpath=$ENV{PWD}."/".$1
}
---cut---
but I guess, there must be a more simple solution!!!
thx
michi
Does anyone know, how to get the full-path of the directory of the perl-script!
This should work from ksh and bash!
my workaround:
---cut---
my $fullpath;
if ( $0=~/(^\/.*?)[^\/]*$/ ){
#if called with fullpath or if script is in a ENV{PATH}-directory
$fullpath=$1;
}else{
$0=~/(.*?)[^\/]*$/;
$fullpath=$ENV{PWD}."/".$1
}
---cut---
but I guess, there must be a more simple solution!!!
thx
michi
$fullpath = $cwd/$0;
I forgot the quotes; it should read
$fullpath = "$cwd/$0"; # unix
$fullpath = "$cwd\$0"; # windows
I forgot the quotes; it should read
$fullpath = "$cwd/$0"; # unix
$fullpath = "$cwd\$0"; # windows
Actually, it is not always possible to discover the pathname of the script.
You have to start with $0, that's certain.
If $0 contains a / it is most likely a path relative to the current working directory -- but it may contain .. which will make simple concatenation yield a messy-looking path. There's help for this:
use Cwd qw(abs_path);
$fullpath = abs_path( $0) unless $0 =~ m{/};
Otherwise, you have to see if the name given in $0 appears as a directory entry in one of the elements of $ENV{PATH}.
@dirs = split /:/, $ENV{PATH};
my $path_found;
for (@dirs) {
do { $path_found = $_/$0; last; } if -x $_/$0 ;
}
and that, too, may need to be reformed:
$fullpath = abs_path($path_found);
Putting all of that together....
use Cwd qw(abs_path);
our $fullpath;
my $path_found;
if( $0 =~ m{/} ) {
$path_found = $0;
} else {
for (split /:/, $ENV{PATH}) {
do { $path_found = $_/$0; last } if -x $_/$0;
}
}
if ( $path_found ) {
$full_path = abs_path( $path_found);
} else {
warn "could not locate full pathname for script $0";
}
That will cover most possibilities, but it's still possible to execute something along a path that contains a directory you cannot read, which is one of the ways for it to be impossible to discover the proper name of the script.
You have to start with $0, that's certain.
If $0 contains a / it is most likely a path relative to the current working directory -- but it may contain .. which will make simple concatenation yield a messy-looking path. There's help for this:
use Cwd qw(abs_path);
$fullpath = abs_path( $0) unless $0 =~ m{/};
Otherwise, you have to see if the name given in $0 appears as a directory entry in one of the elements of $ENV{PATH}.
@dirs = split /:/, $ENV{PATH};
my $path_found;
for (@dirs) {
do { $path_found = $_/$0; last; } if -x $_/$0 ;
}
and that, too, may need to be reformed:
$fullpath = abs_path($path_found);
Putting all of that together....
use Cwd qw(abs_path);
our $fullpath;
my $path_found;
if( $0 =~ m{/} ) {
$path_found = $0;
} else {
for (split /:/, $ENV{PATH}) {
do { $path_found = $_/$0; last } if -x $_/$0;
}
}
if ( $path_found ) {
$full_path = abs_path( $path_found);
} else {
warn "could not locate full pathname for script $0";
}
That will cover most possibilities, but it's still possible to execute something along a path that contains a directory you cannot read, which is one of the ways for it to be impossible to discover the proper name of the script.
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SOLUTION
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#!/usr/bin/perl
print `pwd`;
Using the shell command pwd? Works on older versions of Perl as well:)
print `pwd`;
Using the shell command pwd? Works on older versions of Perl as well:)
ASKER
pwd doesn't have to be the script's directory!!!
you can call the perl-script with:
from everywhere:
/home/user/perl/script.pl
from "/home/user/x/y/":
../../perl/script.pl
from "/home/user/perl/"
script.pl
or
./script.pl
an if "/home/user/perl/" is included in $PATH:
from everywhere:
script.pl
michi
you can call the perl-script with:
from everywhere:
/home/user/perl/script.pl
from "/home/user/x/y/":
../../perl/script.pl
from "/home/user/perl/"
script.pl
or
./script.pl
an if "/home/user/perl/" is included in $PATH:
from everywhere:
script.pl
michi
Yes, what you say is quite true. Some of the offered answers have not taken that into account. But the code I offered and the code in the FindBin module do take it into account and should give you the answer you asked for.
oOOOOOPPPSSSS..... - was just offering my thoughts - and it looks like they weren't exactly worth the 2p offered :)
$cwd = cwd();
$fullpath = $cwd/$0;