Converting a string to a character array (char[])

suppose I have

string arg6; //my 6th argument for some function to be called soon

however i have to pass in this argument as a character array, char[]

I tried,

char x[] = arg6.c_str();

but i get some const char* cannot be converted to char[] error...
is there a way to do what I want? I solved my problem by declaring arg6 as a char[] but i still want to know how to convert a string to char[] for my own sake. I do know how to conver it to a char*.

thanks
lapchernAsked:
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tinchosCommented:
Hi lapchern,

try with

char x[256];
char *p = x;

strncpy( p, arg6.c_str(), 256 );


Cheers!

Tincho
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lapchernAuthor Commented:
cheers!
0
skypalaeCommented:
Hi,

The error you mentioned is that compiler cannot convert pointers to arrays (although they are almost the same, it is question of the array size i suppose). So why don't you write your code like this?

string s = "abcd" ;
char *c = (char *) s.c_str () ; // can be 'const char *c = s.c_str ()'

This works ok for me (using VC++ 6.0) ;

S.
0
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