Solved

Index of TTreeView's SubItem

Posted on 2003-11-11
7
300 Views
Last Modified: 2010-04-05
+ABC
|    |__ SubA
|    |__ SubB
|
+XYZ
     |__ SubX
     |__ SubY

When item "ABC" is selected, TTreeView.Selected.Index returns 0; when SubItem "SubA" or "SubB" is selected, it also returns 0 !!  So how can I differentiate which item/subitem is being selected ??

Thank You.

raymng
0
Comment
Question by:Raymond
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7 Comments
 
LVL 27

Expert Comment

by:kretzschmar
ID: 9721033
this could not be

how do you do evaluate the index
0
 
LVL 5

Expert Comment

by:snehanshu
ID: 9721132
raymng,
  You would have to recursively traverse the parents of the selected treenode till you get a nil parent. Something like this (Where the GetIndexStr procedure will build a comma-separated index string for you):

procedure TForm1.Button1Click(Sender: TObject);
Var
  MyStr: String;

Procedure GetIndexStr(MyNode: TTreeNode; Var MyIndexStr:String);
begin
 If MyNode.Parent <> nil then
   GetIndexStr(MyNode.Parent, MyIndexStr)
 Else
   MyIndexStr := '';
 MyIndexStr := MyIndexStr +','+inttostr(MyNode.index);

end;

begin

  ShowMessage(IntToStr(TreeView1.Selected.Index));
  GetIndexStr(TreeView1.Selected, MyStr);
  ShowMessage(MyStr);

end;
0
 
LVL 5

Expert Comment

by:snehanshu
ID: 9721169
Or you could get the indexes in an array like:

unit Unit1;

interface

uses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, StdCtrls, ComCtrls;

type
  AOI = Array Of Integer;
  TForm1 = class(TForm)
    TreeView1: TTreeView;
    Button1: TButton;
    ListBox1: TListBox;
    procedure Button1Click(Sender: TObject);
  private
    { Private declarations }
  public
    { Public declarations }
  end;

var
  Form1: TForm1;

implementation

{$R *.dfm}

procedure TForm1.Button1Click(Sender: TObject);
Var
  MyStr: String;
  MyAry: AOI;
  i: Integer;

Procedure GetIndexAry(MyNode: TTreeNode; Var Ary: AOI);
begin
 If MyNode.Parent <> nil then
   GetIndexAry(MyNode.Parent, Ary)
 Else
   SetLength(Ary, 0);

 SetLength(Ary, Length(Ary) + 1);
 Ary[High(Ary)] := MyNode.Index;

end;


begin

//  ShowMessage(IntToStr(TreeView1.Selected.Index));
  GetIndexAry(TreeView1.Selected, MyAry);
  ListBox1.Items.Clear;
  For i := low(MyAry) To High(MyAry) Do
  Begin
    ListBox1.Items.Add(inttostr(MyAry[i]));
  End;



end;

end.
0
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LVL 27

Expert Comment

by:kretzschmar
ID: 9721172
use absoluteIndex instead index to get an unique index
0
 

Author Comment

by:Raymond
ID: 9721278
kretzschmar:

Could you please give me an example on how to use the "AbsoluteIndex" ?

raymng
0
 
LVL 27

Accepted Solution

by:
kretzschmar earned 150 total points
ID: 9721299
well, its simple

procedure TForm1.Button1Click(Sender: TObject);
begin
  showmessage(inttostr(treeview1.selected.absoluteindex));
end;

meikl ;-)
0
 

Author Comment

by:Raymond
ID: 9721541
Thanks.
0

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