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how to insert button in string grid

Posted on 2003-11-12
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Last Modified: 2010-04-05
hi
      iam using delphi7 with ado2.1.iam using string grid in my form.i want to insert button in string grid.like when i click any row of a particular column a button should be visible.to be more precise say if i have four columns i want a button to be visible in second column when i click a row of that column


thanx
abu
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Question by:abunectar
1 Comment
 
LVL 23

Accepted Solution

by:
Ferruccio Accalai earned 200 total points
ID: 9738815
Here an example....

unit Unit1;

interface

uses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, Grids, Buttons, StdCtrls;

type
  TForm1 = class(TForm)
    StringGrid1: TStringGrid;
    btn: TButton;
    procedure StringGrid1SelectCell(Sender: TObject; ACol, ARow: Integer;
      var CanSelect: Boolean);
    procedure btnClick(Sender: TObject);
    private
    { Private declarations }
  public
    { Public declarations }
  end;

var
  Form1: TForm1;
  col, Row: Integer;
implementation

{$R *.dfm}
procedure TForm1.StringGrid1SelectCell(Sender: TObject; ACol,
  ARow: Integer; var CanSelect: Boolean);
var
sel: TRect;
begin
If Acol = 2 then begin
      Sel := StringGrid1.CellRect(Acol, Arow);
      SetWindowPos(btn.Handle, { handle }
              0,
              (StringGrid1.Left + 1) + ((Sel.Right )- (sel.Bottom-sel.Top)),
              Sel.Top + StringGrid1.top + 2,
              (sel.Bottom-sel.Top),
              Sel.Bottom - Sel.top ,
              SWP_NOZORDER or SWP_SHOWWINDOW);
      col := ACol;
      Row := ARow;
      btn.Show;
   end else btn.Hide;
end;

procedure TForm1.btnClick(Sender: TObject);
begin
 SHowMessage('Selected Row '+IntToSTr(Row)+ ' in Column '+IntToSTr(Col));
end;

end.

F68 ;-)
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