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Table Long datatype and ADO adInteger parameter datatype

Posted on 2003-11-13
2
2,328 Views
Last Modified: 2008-03-06
I must be dense today :-)

I have an Access database that I am using in SQL Server Compatible Syntax (ANSI 92) mode, not that I think this matters but I am trying to be thorough.

I have a parameterized query:
PARAMETERS ErrLogApp Text ( 255 ), ErrLogNo Long, ErrLogDesc Text ( 255 ), ErrLogMod Text ( 255 ), ErrLogProc Text ( 255 ), ErrLogUser Text ( 255 );
INSERT INTO ztblErrLog ( ErrLogApp, ErrLogNo, ErrLogDesc, ErrLogMod, ErrLogProc, ErrLogUser )
SELECT [ErrLogApp] AS F1, [ErrLogNo] AS F2, [ErrLogDesc] AS F3, [ErrLogMod] AS F4, [ErrLogProc] AS F5, [ErrLogUser] AS F6;


I have a public procedure signature:
Public Sub LogError(ByRef ErrLogMod As String, _
                    ByRef ErrLogProc As String, _
                    ByRef ErrLogNo As Long, _
                    ByRef ErrLogDesc As String, _
                    ByRef ErrLogDisp As Boolean)

inside this procedure I create / append a paramter object to my command object ...
    Set prm = cmd.CreateParameter(Name:="ErrLogNo", _
                                  Type:=adInteger, _
                                  Direction:=adParamInput, _
                                  Value:=ErrLogNo)
    cmd.Parameters.Append prm

when I execute:
    cmd.Execute , , adExecuteNoRecords

I get a "-2147217913: Datatype mismatch in criteria expression" error

I left out the rest of the code because if I skip executing the above posted parameter everything works just fine.

TIA,
Steve
0
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Question by:stevbe
2 Comments
 
LVL 39

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stevbe earned 0 total points
ID: 9748004
It was not the code it was the query.

The query parameters MUST be in the same ordinal position as they are used in the query.

PARAMETERS ErrLogApp Text ( 255 ), ErrLogMod Text ( 255 ), ErrLogProc Text ( 255 ), ErrLogNo Long, ErrLogDesc Text ( 255 ), ErrLogUser Text ( 255 );
INSERT INTO ztblErrLog ( ErrLogApp, ErrLogMod, ErrLogProc, ErrLogNo, ErrLogDesc, ErrLogUser )
SELECT [ErrLogApp] AS F1, [ErrLogMod] AS F2, [ErrLogProc] AS F3, [ErrLogNo] AS F4, [ErrLogDesc] AS F5, [ErrLogUser] AS F6;

Steve
0

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