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Stored Procedure to return values from x to y with increment z

Posted on 2003-11-15
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This is simple (I think), just have not done anything like it yet

If a table has values x, y, and z

(where x is "low value", y is High value" and z is "increment")

in a row I am calling with variable "a", how do I return a set of rows that start with x, end with y, and move upwards with the increment z?

for example, x=2, y=10, z=2

the stored procedure returns

1- 2
2- 4
3- 6
4- 8
5- 10

thanks! It is urgent I learn this asap to forward my project.
0
Question by:JCMcNeil
• 6
• 4

LVL 6

Expert Comment

Could you post the table structure, or at least the columns of interest, and indicate which column(s) contain the low, high, and increment?

I'm not getting the question.
0

LVL 22

Expert Comment

Not getting the question either. This isn't what you meant or is it?

declare @x int, @y int, @z int

set @x = 2
set @y = 10
set @z = 2

declare @current int
set @current = @x

declare @tmp table(id int identity(1,1) not null, [index] int)

while @current<=@y
begin
insert into @tmp values(@current)
set @current = @current + @z
end

select * from @tmp
0

Author Comment

CJ_S, it looks like you are getting the idea, but the sp you wrote didn't return any records, which I need.

Let me see if I can be more clear:

There is a table that contains "start" (x), "end" (y) and "increment" (z) values. A variable (a) calls the correct row.

upon selecting that row, new rows need to be returned that start with x and increase by increment z until they end up at y.

does that make more sense? Sorry I am not familiar enough with sql terminology to explain better.

0

LVL 22

Expert Comment

Works fine for me:

declare @a int

-- inner parameters
declare @x int, @y int, @z int

select @x = start, @y = end, @z = increment from YOURTABLE

declare @current int
set @current = @x

declare @tmp table(id int identity(1,1) not null, [index] int)

while @current<=@y
begin
insert into @tmp values(@current)
set @current = @current + @z
end

select * from @tmp
0

LVL 22

Expert Comment

Oh, one more change:
select @x = start, @y = end, @z = increment from YOURTABLE
should be:
select @x = start, @y = end, @z = increment from YOURTABLE where id=@a
0

Author Comment

It all looks good but I keep getting "the stored procedure executed correctly but did not return any records"
0

LVL 22

Expert Comment

Here's a full sample which also creates a RES table with the values. This is a full example

drop table RES

create table RES
(
id int identity(1,1) not null constraint RES_PK_id PRIMARY KEY,
start int not null,
[end] int not null,
increment int not null
)

insert into RES values(4, 10, 2)

declare @a int
declare @x int, @y int, @z int

set @a = 1

select @x = start, @y = [end], @z = increment from RES

declare @current int
set @current = @x

declare @tmp table(id int identity(1,1) not null, [index] int)

while @current<=@y
begin
insert into @tmp values(@current)
set @current = @current + @z
end

select * from @tmp
0

LVL 22

Accepted Solution

CJ_S earned 500 total points
oh, and it does work for me so if this does not return any results for you, you might want to check out the actual values in your table.
0

Author Comment

how strange, I copied the full example into a stored procedure and still got   "the stored procedure executed correctly but did not return any records"

I am using sql server 2000 controlled through an ACCESS 2002 project and here is all the text from the SP:

ALTER PROCEDURE StoredProcedure19

AS
drop table RES

create table RES
(
id int identity(1,1) not null constraint RES_PK_id PRIMARY KEY,
start int not null,
[end] int not null,
increment int not null
)

insert into RES values(4, 10, 2)

declare @a int
declare @x int, @y int, @z int

set @a = 1

select @x = start, @y = [end], @z = increment from RES

declare @current int
set @current = @x

declare @tmp table(id int identity(1,1) not null, [index] int)

while @current<=@y
begin
insert into @tmp values(@current)
set @current = @current + @z
end

select * from @tmp

0

Author Comment

OK, it works when pulled into the datagrid, I just couldn't see it directly in the stored procedure- thanks!
0

LVL 22

Expert Comment

0

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