How to sort data, inside the XML file, by using XSLT

Posted on 2003-11-16
Last Modified: 2010-04-16
I am trying to sort the xml file's <Name> with XSLT but no luck so far.
Using Windows Application, not Web one.  The form has two datagrids--one for Planet,
another one for PlanetData.  One button for XSLT.  Other buttons for
loading/saving xml file's data.



<?xml version="1.0" encoding="UTF-8" ?>

            <Mass>0.0553(Earth = 1)</Mass>
            <Mass>0.815(Earth = 1)</Mass>
            <Mass>1.0(Earth = 1)</Mass>


[PlanetSort.xslt] (I dont know if these codes are incorrect...)

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="">
      <xsl:template match="Planets">
            <xsl:sort select="Name"/>


I have some difficulties trying to write codes for the XSLT button. I cannot
transform (sort) them properly.

private void button1_Click(object sender, System.EventArgs e)
      string fn1 = "Planets.xml";
      string fn2 = "Sorted_Planets.xml";
      string fnx = "PlanetSort.xslt";

      FileStream fin = new FileStream(@fn1, FileMode.Open);
      XmlTextReader xr = new XmlTextReader(fin);
      System.Xml.XPath.XPathDocument xpd = new System.Xml.XPath.XPathDocument(xr);
      System.Xml.Xsl.XslTransform xslt = new System.Xml.Xsl.XslTransform();

      //  problems here...
      FileStream fout = new FileStream(@fn2, FileMode.Create);
      XmlTextWriter xw = new XmlTextWriter(fout, System.Text.Encoding.GetEncoding("UTF-8"));
      xw.WriteProcessingInstruction("xml", "version=\"1.0\" encoding=\"UTF-8\" ");
      xw.Formatting = Formatting.Indented;
      xslt.Transform(xpd, null, xw);


Don't know if XSLT is useful but if you have different better methods, please let me know.
Advices, examples will be appreciated.  Thank you :)
Question by:rizel

Accepted Solution

alkonaut earned 250 total points
ID: 9762516
You have to specify a valid xpath expression pointing to the element you wish to sort on. e.g. if you want to output the 3 planet nodes sorted by name you'd write

<xsl:template match="Planets">
  <xsl:apply-templates select="Planet">
    <xsl:sort select="Name"/>

beacuse now you can see the path /PlanetData/Planet/Name

otherwise you could also use <xsl:sort select="Planet/Name"/> under Planets, but the nodes <PlanetData> have no element <Name> so they cannot be sorted on name.

Author Comment

ID: 9888158
thanks :)

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