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!! operator

edit - - i get it
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jini555
Asked:
jini555
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1 Solution
 
DexstarCommented:
jini555:

> int i = !! (SHORT) j;

! = Boolean NOT
!! = Boolean NOT NOT

It's silly, but that's what it means.  You should avoid using it.  It is the same as saying this:
   int i = (j != 0);

Hope That Helps,
Dex*
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Kent OlsenData Warehouse Architect / DBACommented:


Depending on the compiler, optimization, and the mood of the guy implementing this, the two "!" operators may cancel each other out.

But in real life, they don't.  The first "!" operator (actually, the righter-most of the two) implicitly converts (short)j to a boolean value so that the result will be 0 or 1.  The second "!" operator then complements the value so that the net effect is the same as:

  int i = ((short)j) ? 1 : 0;



Kent
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Kent OlsenData Warehouse Architect / DBACommented:

Isn't it amazing how many "other ways" there are to do things in C?

:)

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DexstarCommented:
Kent:

Yeah it is.  These two are equivilant:
     int i = ((short)j) ? 1 : 0;

And:
     int i = (j != 0);

Dex*
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Kent OlsenData Warehouse Architect / DBACommented:

Actually, they're not.

if *j* is a variable type that is longer than a short, then your test MAY fail depending on the value of *j*.  You need to recast it as a short (to truncate the upper bits) before testing its value.

But with that small change, we do have three ways to do the same thing that I'd do in two lines of assembler.  :)

Kent
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