user input

hey,

i was just wondering if somebody could give me a code example and syntax for gtting user input in a java application through dos?

i saw a way of doing it on a site but it looked a bit overdone. i just want it nice and simple. if possible as simple as in vb! also fromwhat i could make out the input is has to be equal to a string format. So how so i convert this string into an int and long etc for calculations? is there a parseint or something. another example would be handy.

as ever all input it welcom and appreciated

thanks

dinny
dirtydinnyAsked:
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sre23Commented:
public class Test
{
     public static void main(String args[])
     {
          System.out.print("What is your age?");
          BufferedReader r = new BufferedReader(new InputStreamReader(System.in));  
          int age = Integer.parseInt(r.readLine());
     }
 


}
0
sre23Commented:
this prompts the user for their age and waits for them to enter it and press enter.  When the user hits enter the value they have typed gets assigned to "age"  You will also need to make sure they have typed a number, otherwise you will get an error
0
sre23Commented:
Actually this code will compile

import java.io.*;

public class Test
{
    public static void main(String args[])
    {
       try
       {
         System.out.print("What is your age?");
         BufferedReader r = new BufferedReader(new InputStreamReader(System.in));  
         int age = Integer.parseInt(r.readLine());
         System.out.println("Your Age: " + age);
       }
       catch(IOException e)
       {
           System.out.println("You must enter a number!");
       }
    }



}
0
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lwinkenbCommented:
A small change to sre23's code:

import java.io.*;

public class Input
{
    public static void main(String args[])
    {
       try
       {
         System.out.print("What is your age?");
         BufferedReader r = new BufferedReader(new InputStreamReader(System.in));  
         int age = Integer.parseInt(r.readLine());
         System.out.println("Your Age: " + age);
       }
       catch(NumberFormatException e)
       {
           System.out.println("You must enter a number!");
       }
       catch(IOException e) {
             System.out.println(e);
       }
    }
}
0
sre23Commented:
good point lwinkenb :)
0
dirtydinnyAuthor Commented:
hey lwinkenb


can u comment ur code, just so i know whats going on? i've a fair idea in some parts what it happening but just to get the full picture

thnaks

dinny
0
sre23Commented:
Here I'll do it for ya:

A small change to sre23's code:

import java.io.*;

public class Input
{
    public static void main(String args[])
    {
       try
       {
         System.out.print("What is your age?");  //prints this to the screen and waits for users response
         BufferedReader r = new BufferedReader(new InputStreamReader(System.in));   //creates a BufferedReader object to  
                                                                                                                             //read in from the keyboard (System.in)
         int age = Integer.parseInt(r.readLine());  //when the user hits enter this assigns what they typed to the variable "age"
                                                                     //Integer.parseInt tries to convert what they typed to an Integer
         System.out.println("Your Age: " + age);   //this prints out what number the person entered if it was an integer
       }
       catch(NumberFormatException e)
       {
           System.out.println("You must enter a number!");  //this error is caught if they did not enter an integer
       }
       catch(IOException e) {
            System.out.println(e);   //this error is caught if there was a problem reading in from the keyboard
       }
    }
}
0

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dirtydinnyAuthor Commented:
just one final ammendment!

if i have a double lets cll it sAnswer how do i convert it back to a int before i output it with a preintln statement?

thankd

dinny
0
sre23Commented:
you just need to typecast

int integerValue = (int)sAnser;

putting (int) in front of the value converts it to an integer.
0
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