Read a c STRUCT from a socket connection


I have a existing  application that consists of several proceses that cumunicate with each other using TCP/IP sockets. The application runs on HP-UX and was written in c.

I want to redevelop one of the processes in Java. The process must be able to read the c struct from the socket and write back return messages aswell.

the struct i sdefined as

#define EVENT_MESSAGE struct event_message_struct
EVENT_MESSAGE {
     char id[8];
     char event_code[4];
     char request_handle[12];
     char filename[40];
};

I can connect to the socket
but using a DataInputstream and readline() results in carbage.

pfgroblerAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

girionisCommented:
 What jdk are you using?

  From the javadocs:

"Deprecated. This method does not properly convert bytes to characters. As of JDK 1.1, the preferred way to read lines of text is via the BufferedReader.readLine() method. Programs that use the DataInputStream class to read lines can be converted to use the BufferedReader class by replacing code of the form:

     DataInputStream d = new DataInputStream(in);


with:

     BufferedReader d
          = new BufferedReader(new InputStreamReader(in));"

0
girionisCommented:
 Also note that a character in Java is 16 bits while in C it is 8...
0
lwinkenbCommented:
Try sending string representations of the data that is in the struct.  Then if you read them on the java side using a BufferedReader, you dont have to worry about the 16 bit vs 8 bit thing.
0
Cloud Class® Course: SQL Server Core 2016

This course will introduce you to SQL Server Core 2016, as well as teach you about SSMS, data tools, installation, server configuration, using Management Studio, and writing and executing queries.

CEHJCommented:
In order not to break the sending app, 'take it as its word':

byte[] id = new byte[8];
byte[] event_code = new byte[4];
byte[] request_handle = new byte[12];
byte[] filename = new byte[40];
DataInputStream dis = DataInputStream(in);
dis.read(id);
dis.read(event_code);
dis.read(request_handle);
dis.read(filename);
dis.close();


then you can convert those byte arrays into something more usable. Let us know if you need help doing that once it's working.
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
CEHJCommented:
Or, better:

int id = dis.readInt();
char event_code = dis.readChar();
dis.read(request_handle);
String _filename = new String(dis.read(filename));
0
CEHJCommented:
...and yet another improvement ;-)

int event_code = dis.readUnsignedShort();
0
Igor BazarnyCommented:
CEHJ, are you sure about the byte order? Java definitely uses small-endian, but I personally don't know HP-UX byte order. If it's different, your initial variant with arrays might be better.
0
CEHJCommented:
I would think it should be OK. Applications pushing out data over sockets should use network byte order (little-endian)
0
Igor BazarnyCommented:
If structure is defined as in the intitial post, bytes won't be reordered--fields declared as byte arrays, not multibyte integers. The question remains whether that fields mean multibyte integers. What applications are pushing, IMO often depends on developer expectations and lazyness. If it is known that other end will run on the same platform, byte ordering qustion may seem non-issue. Until someone forgets initial assumption and tries to start inter-platform communication.
0
CEHJCommented:
Well - the ordering should be apparent pretty soon ;-)
0
pfgroblerAuthor Commented:
I have some sucsess  the datatype was CHAr and not byte .
But using :

    char[] id = new char[8];
    char[] event_code = new char[4];
    char[] request_handle = new char[12];
    char[] filename = new char[40];


   System.out.println("START");
   System.out.println(d.read(id)  + " : " + String.valueOf(id));
   System.out.println(d.read(event_code) + " : " + String.valueOf(event_code) );
   System.out.println(d.read(request_handle)+ " : " + String.valueOf(request_handle) );
   System.out.println(d.read(filename)+ " : " + String.valueOf(filename) );

The result that I get is :
8 : GMD
4 : 00  
12 : 760952@
40 : 00760952.msgè@`+ è@

id and eventcode is fine but request_handle and  filename includes some garbage at the end. I asume that is because the data is shorter than the actual space allocated to it . How can I insure only the relavant data is read ?
0
Igor BazarnyCommented:
Note that java char is 2-byte, while C char is one byte. You have to read bytes. It seems that your char arrays get implicitly casted to byte arrays--there are no methods accepting char arrays in DataInputStream. Garbage at the end caused by not interpreting \0 as terminator--java straings can have embedded \0.
0
CEHJCommented:
Yes, read it into byte arrays. The handle field is numeric is it not? For the filename, i'd use a similar approach to the following:

            byte[] filename = { 'a', 'b', 'c', '\0', '\1', '\2', '\3' };
            boolean zeroOut = false;
            for(int i = 0;i < filename.length;i++) {
                  if (filename[i] == '\0') {
                        zeroOut = true;
                  }
                  if (zeroOut) {
                        filename[i] = 0;
                  }
            }
            System.out.println(new String(filename));
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Java

From novice to tech pro — start learning today.