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Casting doubles to integer problem

Posted on 2003-11-23
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Last Modified: 2010-03-31
Hiya

I have a small problem when trying to cast a double precision number to an integer:  

When I input a double number into my program (its a command line program) I want to immediatly multiply it by 100 and convert it to an integer.  The user should always be inputing numbers with no more than 2 decimal places as it will always be an amount of money.  

Basically it usually works for most numbers, but certain numbers such as 19.99 gets converted to 1998 (or 1998.99999999999 when I output the multipled double).  

I was just wondering if there was a simple fix for this.
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Question by:antt
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5 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 9806260
The manipulation of floating point values is constrained by degrees of precision - they frequently therefore end up as approximations. For arbitrary precision, use the BigDecimal class:

    String s = "19.99";
    double d = Double.parseDouble(s);
    System.out.println(s + " (parseDouble) -> " + d * 100);
    BigDecimal bd = new BigDecimal(s);
    d = bd.doubleValue();
    System.out.println(s + " (BigDecimal) -> " + d);
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LVL 15

Expert Comment

by:JakobA
ID: 9806630
double d = Double.parseDouble("19.99");
int cents = Math.round( d * 100 );
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LVL 15

Accepted Solution

by:
JakobA earned 25 total points
ID: 9806636
Oops. it needs an explicit cast:
int cents = (int)Math.round( d * 100 );
0
 

Author Comment

by:antt
ID: 9809882
dammit still doesnt work
0
 

Author Comment

by:antt
ID: 9809896
oh wait yes it does

i cant count
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