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# Sorting the values of hashtable

Posted on 2003-11-23
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This is my part of code..I have hashtable, docIdTable.
CosSimilarity class has two members, DocId and Similarity.
I want to display with sorted Similarity(mainly) and DocId.
Based on this code, it will display..

DocID     Sim
344       33.44
323       23.22
567       12.23
766       12.23
345       12.23

It will sort by similarity. If same similarity, how can I sort by DocID? Thank you

DocID     Sim
344       33.44
323       23.22
345       12.23
567       12.23
766       12.23

ArrayList toArrayList = new ArrayList(docIdTable.values());
object[] toArray = toArrayList.toArray();
Arrays.sort(toArray);

for(int i=0; i<toArray.length; i++){
buf.append(((CosSimilarity)toArray[i]).getDocId());
buf.append(((CosSimilarity)toArray[i]).getSimilarity());
}

public int compareTo(Object o) {
if (o instanceof CosSimilarity) {
CosSimilarity t = (CosSimilarity) o;
return compareTo(t);
}throw (new ClassCastException());
}

public int compareTo(CosSimilarity t) {                                    if(t.similarity > this.similarity){
return 1;
}else if(t.similarity == this.similarity){
return 0;
}else{
return -1;
}
}

0
Question by:horizzang
1 Comment

LVL 2

Accepted Solution

smitty22 earned 50 total points
ID: 9808233
Write another compareTo method that compares DocIDs.  Modify your compareTo( Object o ) method so that if compareTo( CosSimilarity t ) returns 0, it makes a call to compareTo( DocID d ) to determine the relation.
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