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average using the 4 highest scores of the 5 enterd

Posted on 2003-11-24
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Last Modified: 2010-04-01
need help to find the averge of the 4 highest test scores
out of the 5 that were entered i think i need a func but i'm having trouble setting it  up..

#include <iostream>
#include <iomanip>
using namespace std;


void EvalGrade ( int Grade);
void FindAve (float Ave);
void Minimum(float,float,float,float,float);
{
  char letterGrade;
please email me a911hoe@msn.com with answ
 

   switch ( Grade/10)
   {
      case 10:
        case 9:
           
              letterGrade = 'A';
                break;

        case 8:
                 letterGrade = 'B';
                 break;

        case 7:
                letterGrade = 'C';
                break;

        case 6:
                letterGrade = 'D';
                break;

        case 5:
        case 4:
        case 3:
        case 2:
        case 1:
        case 0:
                letterGrade = 'F';



   }

   cout << "The letter grade is: " << letterGrade << endl;
   cout << "The Average is :" << ave << endl;
}

void main()

 {

     float Minimum(float test1,float test2, float test3, float test4, float test5)

         if (test1 < test2 && test1 < test5)
                return test1;
          if (test2 < test1 && test2 < test5)
               return test2;
          if (test3 < test1 && test3 < test5)
               return test3;
          if (test4 < test1 && test4 < test5)
               return test4;
          if (test5 < test1 && test5 <test4)
               return test5;

      FindAve

        Ave = test1 + test2+ test3 +test4 + test5 - Minimum / 4;
     
     return Ave


  int Grade;

   cout <<"Please enter Test 1\n ";
   cin >> Grade;

   EvalGrade ( Grade);

   cout << "Please enter Test 2\n";
   cin >> Grade;

   EvalGrade ( Grade);

   cout << "Please enter Test 3\n";
   cin >> Grade;

   EvalGrade ( Grade);

   cout << "Please enter Test 4\n";
   cin >> Grade;

   EvalGrade ( Grade);

   cout << "Please enter Test 5\n";
   cin >> Grade;

    EvalGrade ( Grade);
 


}
 


0
Comment
Question by:tbell000
  • 3
  • 2
  • 2
  • +2
10 Comments
 

Author Comment

by:tbell000
ID: 9815835
thanks for your help yesterday hope you can help today
also i have not accepted any ones answers
so all the points are your if you are correct
0
 
LVL 4

Expert Comment

by:n_fortynine
ID: 9815883
tbel000, I don't understand why you now have 3 questions asking about the same problem. Please keep working with the other experts who helped you in the last 2 threads and get things straightened out. They also need to receive credits for helping you as well. Please close two of these open questions as I suggested in the other thread.
0
 
LVL 4

Expert Comment

by:n_fortynine
ID: 9815886
0
Optimizing Cloud Backup for Low Bandwidth

With cloud storage prices going down a growing number of SMBs start to use it for backup storage. Unfortunately, business data volume rarely fits the average Internet speed. This article provides an overview of main Internet speed challenges and reveals backup best practices.

 
LVL 24

Accepted Solution

by:
shivsa earned 500 total points
ID: 9815889
#include <iostream>
#include <iomanip>
using namespace std;

void EvalGrade ( int Grade);
int Minimum(int test1, int test2 , int test3, int test4, int test5);

void EvalGrade(int Grade)
{
  char letterGrade;

   switch ( Grade/10)
   {
      case 10:
        case 9:
           
              letterGrade = 'A';
                break;

        case 8:
                 letterGrade = 'B';
                 break;

        case 7:
                letterGrade = 'C';
                break;

        case 6:
                letterGrade = 'D';
                break;

        case 5:
        case 4:
        case 3:
        case 2:
        case 1:
        case 0:
                letterGrade = 'F';
   }
   cout << "The letter grade is: " << letterGrade << endl; }

int  Minimum(int test1,int test2,int  test3,int  test4, int test5) {

         if (test1 < test2 && test1 < test5)
                return test1;
          if (test2 < test1 && test2 < test5)
               return test2;
          if (test3 < test1 && test3 < test5)
               return test3;
          if (test4 < test1 && test4 < test5)
               return test4;
          if (test5 < test1 && test5 <test4)
               return test5;
}

int main()
 {

  int Grade;
        int test1, test2, test3, test4, test5;
        float Ave;
        int min;

   cout <<"Please enter Test 1\n ";
   cin >> test1;
   EvalGrade ( test1);
   cout << "Please enter Test 2\n";
   cin >> test2;
   EvalGrade ( test2);
   cout << "Please enter Test 3\n";
   cin >> test3;
   EvalGrade ( test3);
   cout << "Please enter Test 4\n";
   cin >> test4;
   EvalGrade ( test4);
   cout << "Please enter Test 5\n";
   cin >> test5;
    EvalGrade ( test5);
        min = Minimum(test1,test2,test3,test4,test5);  
     Ave =(float)((test1 + test2+ test3 +test4 + test5 - min) / 4);
       
   cout << "The Average is : " << Ave << endl;
       

}
0
 
LVL 24

Expert Comment

by:shivsa
ID: 9815928
correction change last 3 lines with this. aftre min = Minimum(......);

Ave =(float)(test1 + test2+ test3 +test4 + test5 - min) /((float) 4);
        cout.setf(ios::showpoint);
   cout << "The Average is : " << Ave << endl;
0
 
LVL 24

Expert Comment

by:shivsa
ID: 9815939
please let us know if u have more questions.
0
 
LVL 3

Expert Comment

by:monkesdb
ID: 9816026
here's a real nice way to do it. you won't beleive how short this thing is.

#include <vector>
#include <algorithm>
#include <numeric>

...

int main()
{
    float tmp;
    vector<float> grades = new vector();

    for(int i = 1; i < 6; i++)
    {
        cout << "Please enter Test " << i << "\n";
        cin >> tmp;
        grades.push_back(tmp);
    }

    float total = accumulate(grades.begin(), grades.end(), 0);
    float minimum = min_element(grades.begin(), grades.end());

    float average = (total - minimum) / 4.0;
}
0
 
LVL 3

Expert Comment

by:monkesdb
ID: 9816034
add a

using namespace std;

in there (i always forget before i compile it the first time)
0
 
LVL 9

Expert Comment

by:tinchos
ID: 10285810
No comment has been added lately, so it's time to clean up this TA.
I will leave the following recommendation for this question in the Cleanup topic area:

Accept: shivsa {http:#9815889}

Please leave any comments here within the next seven days.
PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

Tinchos
EE Cleanup Volunteer
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