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Find the Path and Version of Applications which installed in Window2000 by using Visual C++

Posted on 2003-11-25
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Dear all,

Can you help me to find the Path and Version of all Applications which installed in Window2000 by using Visual C++?

I mean applications that you can see them in Add/Remove Programs Control Panel.

Thanks in advance !

DungNgo.
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Question by:dungngo
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4 Comments
 
LVL 32

Expert Comment

by:jhance
ID: 9816767
This is not a C++ language question and it off topic here.  A much better place for this would be the WINDOWS PROGRAMMING topic area:

http://www.experts-exchange.com/Programming/Programming_Platforms/Win_Prog/

You should post a comment for the moderator in the CS topic area:

http://www.experts-exchange.com/Community_Support/

and ask them to move your question to the right topic area.  It helps things all around and benefits you by getting Windows Programming experts on your question vs. C++ experts here.
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LVL 39

Accepted Solution

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itsmeandnobodyelse earned 500 total points
ID: 9816811
You'll find the programs  in the Windows registry

       HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall

Any subkey represents

You may open the key using RegOpenKeyEx, e. g.


    HKEY  hkeyTop   = HKEY_LOCAL_MACHINE;
    HKEY  hkey      = NULL;
    long  rc        = 0L;
   

    if ((rc = RegOpenKeyEx(hkeyTop,
                "SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Uninstall", 0, KEY_READ, hkey))
          != ERROR_SUCCESS)
    {
        cout << "key SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Uninstall was not found. rc= " << rc << "\n";
        return 2;
    }

Then you might query for all subkeys using RegEnumKey

   char  szSubKey[512] = { '\0' };
   DWORD dwSize = 512;
   DWORD  dwIdx = 0; // index of subkey to enumerate
   while ((rc = RegEnumKey(hkey, dwIdx, szSubKey, &dwSize)
          == ERROR_SUCCESS)
    {
          dwIdx++;
          // do something with szSubKey
          ....
    }

Hope, that helps

Alex

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Expert Comment

by:tinchos
ID: 10285819
No comment has been added lately, so it's time to clean up this TA.
I will leave the following recommendation for this question in the Cleanup topic area:

Accept: itsmeandnobodyelse {http:#9816811}

Please leave any comments here within the next seven days.
PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

Tinchos
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