Retrieving the Appropriate Bits From Data

Hi All,

I have a problem. I will be using VB6 to code an application to retrieve the appropriate bits from the data. This application will communicate with Device 1, whilst Device 2 can only communicate with Device 1. The application in the PC will always poll Device 1 for data, whilst Device 1 will poll Device 2 for data. The data is stored in the buffer of the device. The protocol is as follows:-

<Head><Type><Level><ID><Command><Length><Data>
    01         01       01       01         4fH            n        12bytes

When <Level> = 2, this show that PC is polling for Device 2 data. Device 1 will start to poll data in Device 2 buffer. The data will then transfer from Device 2 buffer to Device 1 buffer. how can I code in VB to send this command to poll for device 2. After getting the data, how can i abstract the last 6 bytes from the data and drop the first 6 bytes?

thanks you
wmchewAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

GrahamSkanRetiredCommented:
I think you will have to explain more about your scenario.

Are you able to communicate OK with your devices?

Assuming you are, it appears to be a matter of manipulating strings.

If all you need to poll device 2 is to change the level then

Device2Data = Left$(Device1Data,2) & chr$(02) & Mid$(Device1Data, 3)
 
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
GrahamSkanRetiredCommented:
And to drop the first 6 bytes

strRestOfBuffer = Mid$(strFullBuffer, 7)

0
wmchewAuthor Commented:
hi GrahamSkan,

Ok. Let me be more detail. I have this application(coded in VB6) in PC monitoring 2 card access readers. They are both installed on a different floor of a building. These access readers actually stores the swipe card records in the readers. this application will always poll for data from reader in the 1st level(the one nearest PC) whilst PC can only communicate with reader 2 through reader 1.

As you can see from the protocol, when the level = 2, that mean PC wanted to poll data from reader 2(in 2nd level). Then reader 1 will recognise this and poll for data in reader 2 which was stored in buffer. The data was then transferred from reader 2 buffer to reader 1 buffer, finally to PC.

How should I code this part.

Secondly, after getting this data how can I abstract the last 6 bytes of the 12 bytes data?

thanks.
0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

wmchewAuthor Commented:
BTW, the devices can communicate. and the communication standard is RS485.
0
EDDYKTCommented:
To send command


dim str as string

str = chr$(1) + chr$(1) + chr$(2) + ....   ' you get the idea here
MSComm1.Output = str


To extract the data

use GrahamSkan's method


ie

dim str as string

str = MSComm1.Input
str = mid$(str, 13, 6)
0
ArkCommented:
      First_six_bits = (lData And &HFFF000) / &H1000
       Second_six_bits = lData And &HFFF&
0
ArkCommented:
PS.
or reverse according BigEndian/LittleIndian bytes order
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Visual Basic Classic

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.