updating table, then adding new row if new account


Hi,

I need a script that updates the 'status' column in a mysql table if the account number is found, like this:

mysql_query("UPDATE user SET status = '$cust_data[5]' WHERE account = '$cust_data[2]'");

and....   if the account number is not found, inserts a new row with the new account information:

mysql_query("INSERT INTO user VALUES
('$cust_data[0]','$cust_data[1]','$cust_data[2]','$cust_data[3]','$cust_data[4]','$cust_data[5]')");

How do I do that?

Thanks,

Chris

ChrisAndrewsAsked:
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lozlozCommented:
hi,

simple if clause based on the relevant details being selected from a database

<?
$query = "SELECT COUNT(id) AS num FROM user WHERE account='$cust_data[2]'"; // find the row
$result = mysql_query($query) or die("Error in query - " . mysql_error());
$row = mysql_fetch_assoc($result);
if($row["num"]) > 0) { // if there is a row with that account number...
  $query2 = "UPDATE user SET status = '$cust_data[5]' WHERE account = '$cust_data[2]'"; // update it
  $result2 = mysql_query($result2) or die("Error in query - " . mysql_error());
  print "User details updated";
} else {
  $query2 = "INSERT INTO user VALUES ('$cust_data[0]','$cust_data[1]','$cust_data[2]','$cust_data[3]','$cust_data[4]','$cust_data[5]')"; // otherwise add it
  $result2 = mysql_query($query2) or die("Error in query - " . mysql_error());
  print "User's details added";
}
?>

cheers,

loz
0

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ChrisAndrewsAuthor Commented:

Hi Loz,

Thank you, I think this is going to work out great.  Though the script is more advanced than I could write, I can kinda follow along with what's happening.

But when I run it I get a 'parse error' on this line:

if($row["num"]) > 0) {

Do you see what might be causing that?

Thanks again for your help,

Chris
0
lozlozCommented:
sorry that should be

if($row["num"]) > 0)) {

loz
0
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ChrisAndrewsAuthor Commented:

opps, actually:

if($row["num"] > 0 )

figured that out after you added the second one :)

Now I get:

Error in query - Unknown column 'id' in 'field list'

Chris
0
lozlozCommented:
hah my fault for being a little tired..

yeh you need to change the first query to have a field counted (i usually use the id field) but you can use account:

$query = "SELECT COUNT(account) AS num FROM user WHERE account='$cust_data[2]'"; // find the row
0
ChrisAndrewsAuthor Commented:

found and fixed one more bug, now it's working  :)

$result2 = mysql_query($result2) or die("Error in query2 - " . mysql_error());

changed to:

$result2 = mysql_query($query2) or die("Error in query2 - " . mysql_error());

Just noted in case anyone else accesses this question (or I come back to it later).

Thanks again loz, this helps me out a lot,

Chris
0
lozlozCommented:
heh no problem, sorry for the errors i'm being a bit dopey

loz
0
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