Solved

ArrayIndexOutOfBoundsException

Posted on 2003-11-27
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Last Modified: 2010-03-31
Hi Experts!

I have the following code in a program:

 szOperType = new String[nRows];
        for ( i = 0; i <= nRows; i++ )
          szOperType[i] = "";

nRows is an integer and I previously gatter it. szOperType is an array of Strings. I am getting an ArrayIndexOutOfBoundsException when nRows == 0. I do not know why it wont let me create an array of 0...does anyone knows how??

Thank you Experts! I'll give 100 points for it! :)

pupieye
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Question by:pupieye
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LVL 35

Expert Comment

by:TimYates
ID: 9832558
for ( i = 0; i <= nRows; i++ )

should be

 for ( i = 0; i < nRows; i++ )
0
 
LVL 35

Expert Comment

by:TimYates
ID: 9832570
arrays go from index zero, up to (not including) their length

ie:  from zero for [length] number of elements

When you were setting yuor array to length 0, your loop would still try and access element zero

which didn't exist
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LVL 35

Accepted Solution

by:
TimYates earned 100 total points
ID: 9832624
> does anyone knows how??

nRows = 0 ;
szOperType = new String[ nRows ];

you were doing it right..
0
 

Author Comment

by:pupieye
ID: 9833592
I think I know why....When I was trying to create the array

szOperType = new String[ nRows ];

since nRows =0 I was  not creating an array of zero length, so that was my mistake...

Anyway...since you were the only one who answer...those points go to you buddy!

Regards!

Francisco
0

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