Problem: Class B should take values from class A

yes u can A's functions just like u use any other function. remember to put reference to A class.

you can also use...

pA[index].getAny();

if you declare pA like...

pA = new A[100];

but for this you need to give A a public default constructor.

Hi lorcan,

Whenever u create a class, u can either have data-members/functions as public, protected OR private.

Now, U can access public data-members/functions outside the class using a variable/pointer of that particular class.

You cannot access private members/functions from outside the class. i.e. only functions within the class can access other private functions/data-members of that class.

Thus, in your case, you are declaring a pointer to class A in class B.
Thus, u can access ONLY PUBLIC data-members / functions using this pointer. Not to mention, that data-membsrs are normally NOT MADE PUBLIC. Only functions should be normally made PUBLIC. You can always have PUBLIC member functions thru which u can access the data members
You will have to use the deference operator -> as shown in other posts if u use a pointer OR the dot '.' operator if u declare an object of type A in B.

As shown in above posts, u will have to allocate memory to the pointer of type A in constructor
e.g. A *p = new A ;

HTH
Amit

Thank you a lot but that's what i've got so far:
class A
{
    private:
        char *name;
        int number;
        double price;
    public:
        A(char *nameE,int numberE,double priceE);
        A();
        ~A();
        A(A &a);
        A & operator=(A &a);
};
class B
{
    private:
        A *b;        //my array of type A
        int menge, *anzahl;
    public:
        B(A &a);
        B();
        ~B();
};
A::A()
{
    name = new char[1];
    number = 0;
    price = 0.0;
    name[0] = '\0';
}

    and now I want to use:
    1. a default constructor to create b of type A
    2. a constructor to get the values from a into b[0] and b[1] and so on...
    3. copy b into c of Type B