to concatenate with Null

Hi,
a question,

in a table I have two Fields, ID_PESSOA and ID_PESSOA_PAI.
in some cases, the field ID_PESSOA_PAI is null.

How can I make to concatenate the two fields, and case the field ID_PESSOA_PAI is null, return only ID_PESSOA ????

ex:
P.ID_PESSOA = 10;
P.ID_PESSOA = 20;
(P.ID_PESSOA || ' \ ' || P.ID_PESSOA_PAI) PATH
PATH = 10 \ 20;

P.ID_PESSOA = 10;
P.ID_PESSOA_PAI = null;
(P.ID_PESSOA || ' \ ' || P.ID_PESSOA_PAI) PATH
PATH = 10 \;


Thank's
Rafael Schardosin
Porto Alegre - Brazil


schardosinAsked:
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Gary BenadeCommented:
There may be other ways, but all I can think of is this. I hope I understood your question correctly....

select cast( P.ID_PESSOA || ' \ ' || P.ID_PESSOA_PAI as char(25)) result_str from test
where P.ID_PESSOA is not null and P.ID_PESSOA_PAI is not null
union all
select cast( P.ID_PESSOA as char(25)) result_str from test
where P.ID_PESSOA is not null and P.ID_PESSOA_PAI is null
union all
select cast( P.ID_PESSOA_PAI as char(25)) result_str from test
where P.ID_PESSOA is null and P.ID_PESSOA_PAI is not null

Regards
Gary
0
Gary BenadeCommented:
When I re-read your question, I saw that only P.ID_PESSOA_PAI could be NULL, so you can shorten the above to this.

select cast( P.ID_PESSOA || ' \ ' || P.ID_PESSOA_PAI as char(25)) result_str from test
where P.ID_PESSOA_PAI is not null
union all
select cast( P.ID_PESSOA as char(25)) result_str from test
where P.ID_PESSOA_PAI is null
0
schardosinAuthor Commented:
Thank´s,

but the solution more optimized is other,
reading the Firebird Help I  get the following solution:
select
CASE WHEN PP.ID_PESSOA is null then P.ID_PESSOA ELSE PP.ID_PESSOA || ' \ ' || P.ID_PESSOA END PATH
from
  V_PESSOA P left outer join
  V_PESSOA PP on PP.ID_PESSOA = P.ID_PESSOA_PAI


Thank´s
Rafael Schardosin
Porto Alegre - Brazil
0
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Gary BenadeCommented:
I have never heard of the Select CASE statement for FB 1.0.x? Must be a new 1.5 feauture...

Surely all you need to do is

select
CASE WHEN P.ID_PESSOA_PAI is null then P.ID_PESSOA ELSE P.ID_PESSOA || ' \ ' || P.ID_PESSOA_PAI END PATH
from
  V_PESSOA P

Why the join??
0
schardosinAuthor Commented:
sorry,

in a view V_PESSOA for table PESSOA, the field ID_PESSOA_PAI is Daddy of the ID_PESSOA.
to bring the name(field NOME) of ID_PESSOA and ID_PESSOA_PAI, I make a bond between ID_PESSOA_PAI (V_PESSOA P) and ID_PESSOA (V_PESSOA PP) for bring in only one select the name of ID_PESSOA and your Daddy, ID_PESSOA_PAI.

translation.
PAI = DADDY
PESSOA = PEOPLE
NOME = NAME

Rafael Schardosin
Porto Alegre - Brazil
0
BAlexandrovCommented:
If you use firebird, the most correct is to use Coalesce - this is the Ansi standart function

(P.ID_PESSOA || ' \ ' || coalesce(P.ID_PESSOA_PAI,''))


Bojidar Alexandrov
0

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schardosinAuthor Commented:
thank´s

your solution was of great help!!!


Rafael Schardosin
Porto Alegre - Brazil
0
vowcaCommented:
0
kacorretiredCommented:
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