JTree(Vector v) - problems displaying hierarchy

Hi,

In my Applet I want to populate a JTree with a Vector using constructor JTree(Vector v). The Vector contains objects of a class (MyTreeNode) extending DefaultMutableTreeNode interface, some objects are children of others. I was hoping the hierarchi was displayed in the tree, but the tree is "flat", without sub-levels. I tried to add only the top parent objects to the Vector, but their children nodes were not displayed.

How can I get the hierarchi displayed in a JTree using the JTree(Vector v) constructor?



MyTreeNode root = new MyTreeNode("new Result("Result 1"));
MyTreeNode child_1 = new MyTreeNodenew Result("Result 1.1");
MyTreeNode child_2 = new MyTreeNode(new Result("Result 1.2");
MyTreeNode child_11 = new MyTreeNode(new Result("Result 1.1.1");
MyTreeNode child_12 = new MyTreeNode(new Result("Result 1.1.2");
root.add(child_1);
root.add(child_2);
child_1.add(child_11);
child_1.add(child_12);

Vector v = new Vector();
v.add(root);
v.add(child_1);
v.add(child_2);
v.add(child_11);
v.add(child_12);
// ...or...
//v.add(root);//displays only: Result 1

JTree tree = new JTree(v);




I also tried

JTree tree = new JTree(root);

but only root is displayed. I have tried to use a DefaultTreeModel:

DefaultTreeModel model = new DefaultTreeModel(root);
JTree tree = new JTree(model);

but root is the only node displayed...

Thanks for helping!!




MarteJAsked:
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grim_toasterCommented:
The reason all of your nodes are on the same level is that the constructor that takes the Vector has this to say in the API docs:

Returns a JTree with each element of the specified Vector as the child of a new root node which is not displayed
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SuperKarateMonkeyCommented:
Your approach uses the wrong constructor.  I'm afriad the constructor:

JTree( Vector value )

is SUPPOSED to just create a JTree with all the elements in the Vector as the children in a flat tree underneath an undisplayed root.

See the notes under:

http://java.sun.com/j2se/1.4.2/docs/api/javax/swing/JTree.html#JTree(java.util.Vector)
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grim_toasterCommented:
Here's a very simple JTree example that does work, it shouldn't be too hard to modify to your needs:

import javax.swing.JFrame;
import javax.swing.JTree;
import javax.swing.tree.DefaultMutableTreeNode;

public class Thing extends JFrame
{
    public Thing() {
        super("Sample Tree");
        setSize(400, 400);
       
        DefaultMutableTreeNode root = new DefaultMutableTreeNode("top");
        DefaultMutableTreeNode child1 = new DefaultMutableTreeNode("child1");
        DefaultMutableTreeNode child2 = new DefaultMutableTreeNode("child2");
        DefaultMutableTreeNode grandChild = new DefaultMutableTreeNode("grandChild");
       
        root.add(child1);
        root.add(child2);
        child1.add(grandChild);
       
        JTree tree = new JTree(root);
       
        this.getContentPane().add(tree);
        this.show();
    }
   
    public static void main(String[] args) {
        new Thing();
    }
}
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SuperKarateMonkeyCommented:
Yup.  That'll do it.
0
Mick BarryJava DeveloperCommented:
> DefaultTreeModel model = new DefaultTreeModel(root);
> JTree tree = new JTree(model);

That should have worked.

What does MyTreeNode look like?
0
Mick BarryJava DeveloperCommented:
Have you overidden isLeaf() in your MyTreeNode class?
0

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MarteJAuthor Commented:
Sorry for not posting MyTreeNode, that would have made it easier for you all.

Yes, I have overriden isLeaf and other methods of DefaultMutableTreeNode.... Shouldn't do that, should I?

I removed the overidings, and it worked - both

JTree tree = new JTree(root);

and

JTree tree = new JTree(model);

The overridings were left from when I implemented TreeNode interface, but when extending DMTreeNode, its methods should not be overidden. Got it!

Thanks for all help, everybody!!! :-)
0
Mick BarryJava DeveloperCommented:
> Shouldn't do that, should I?

You can, as long as you overide it with the correct behaviour :)
0
Mick BarryJava DeveloperCommented:
0
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