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using if else with Databinder.eval( ) is not letting the code compile

Posted on 2003-12-01
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1,483 Views
Last Modified: 2008-03-10
I have an itemTemplate in a datagrid. I want display an image button or a simple hyper link based upon some field vlaue in "MATRIX_ITEM_TYPE". I simply put the if else condition but that does not seem to work. Any ideas would be highly appreciated. thanks...

<asp:templateColumn>
<itemTemplate>
<tr>
<td colspan=3 align=middle>
<%# if (DataBinder.Eval(Container.DataItem, "MATRIX_ITEM_TYPE") == 3){ %>
<asp:ImageButton ID="itemType" Runat="server" ImageUrl="images/items/custom_configuration.gif"></asp:ImageButton>
<%}else{%>
 <a href="">more info</a>
<%}%>      
</td>
</tr>
</table>
</ItemTemplate>
</asp:TemplateColumn>
0
Comment
Question by:rxraza
  • 3
  • 2
6 Comments
 
LVL 29

Assisted Solution

by:David H.H.Lee
David H.H.Lee earned 50 total points
ID: 9855422
rxraza,
Instead of
<%# if (DataBinder.Eval(Container.DataItem, "MATRIX_ITEM_TYPE") == 3){ %>

Change to
<% if (DataBinder.Eval(Container.DataItem, "MATRIX_ITEM_TYPE") == 3){ %>
-Eliminate "#". What you need is dynamically generate code based on selected criteria, not binding data into <ItemTemplate> in datagrid.

However, there are some others way to solve your problems as well. Please refer my post at this thread :
http://www.experts-exchange.com/Web/Web_Languages/ASP/Q_20806371.html

Regards
x_com
0
 
LVL 3

Accepted Solution

by:
vijay7248 earned 150 total points
ID: 9856272
Hi,
You can use a function and return the value u want ......

Try this workaround:
1. Declare a label inside ur item template like this:
      <ItemTemplate>
       <asp:label runat=server
Text='<%#getpath(DataBinder.Eval(Container.DataItem, "MATRIX_ITEM_TYPE").ToString)%>'>
       </asp:label>
     </ItemTemplate>

2. Then in ur server side script add the function getpath:
       function getpath(ItType As Integer) as string
            dim path as string
                  if ItType=3 then
                     path="<img border=0 src='images/items/custom_configuration.gif' alt='Picture Available'/>"
                  else
                     path="<a href='ur path here'>more info</a>"
                  end if
            return path
       end function


Using a function for this kind of needs will avoid much confusions in the code..

Hope this helps...  :)

-Vijay


0
 

Author Comment

by:rxraza
ID: 9860475
well guys:

Here is the situation. I have modified the code, now the code is as follows:
............
<ItemTemplate>
<%# getDetails(DataBinder.Eval(Container.DataItem, "MATRIX_ITEM_TYPE"))%>
</itemTemplate>
.......

Server Side function is as follows:

getDetails(matrixItemType){
   if (matrixItemType == 3){
      return "<asp:ImageButton ID=itemType Runat=server   ImageUrl=""images/items/custom_configuration.gif""></asp:ImageButton>"      
  }
  else{
     return "<a href="""">more details...</a>"
 }
}

The problem is it is returning the correct element based upon the value in the data grid column but on the page the <asp:ImageButton> is not being rendered.
Any idea about how to render this control on the page? thanks

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LVL 3

Expert Comment

by:vijay7248
ID: 9864413
Hi rxraza,
Happy to see u use my approach.

>>>>>>
The problem is it is returning the correct element based upon the value in the data grid column but on the page the <asp:ImageButton> is not being rendered.
Any idea about how to render this control on the page? thanks
>>>>>>

Why not try the ordinary HTML <img> tag  instead of using the <ASP:Image>
 button.Since u need the functionality of an image button u can put an <img> tag within <a href>.Something like this.......


getDetails(matrixItemType){
   if (matrixItemType == 3){
      return "<a href='currentpage.asp?gofunction=yes'><img border=0 src='images/items/custom_configuration.gif' alt='Picture Available'/></a>"
  }
  else{
     return "<a href="""">more details...</a>"
 }
}

Incase if u r accessing a function/sub (say Sub Test)   using the Image button.....
U can read the queryString in ur PageLoad function as::

           if Request.QueryString("gofunction")="yes" then
                     call Test
           end if

If u jus need to transfer to another page ...then give the filename in the a href..


Hope this works...     :)

-Vijay
0
 

Author Comment

by:rxraza
ID: 9868700
Thanks Vijay for a descriptive explanation. The solution that you mentioned is a workaround, which will always work.

Actually I wanted to know is it possible to render the <asp:ImageButton> once it is dynamically generated
OR
it could only be rendered by the 'dll' responsible for handling .aspx scirpts

thanks in Advance
0
 
LVL 3

Expert Comment

by:vijay7248
ID: 9874109
rxraza,
I'm sure there must be some way or the other to dynamically add a control through coding.
Since u r using Datagrid this could be slightly difficult.
(FYI: I'm new to .Net)

But the thing is, I've not tried that yet . sorry to say this :(
I dont have the time to test a code and give that to you as I've been put into a new project now.

I know you can do it..Jus try adding a control dynamically to the datagrid using some tutorials/helps from www...

or else you can do something similar using the AddColumn functionality of DAtagrids..

Hope this helps :)


-Vijay
0

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