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dynamic table results

hello,
I am trying to find a tutorail to create a dynamic table, what i mean is this, if their are 3 results it will output like this
<tr><td>$output</td><td>$output</td><td>$output</td></tr>

is their is only one then it would be this
<tr><td>$output</td><td>&nbsp;</td><td>&nbsp;</td></tr>

is their is 5 then it would be this
<tr><td>$output</td><td>$output</td><td>$output</td></tr>
<tr><td>$output</td><td>$output</td><td>&nbsp;</td></tr>

I have no idea how to do this with php, i have an sap script, but i cant see using it,, this is my output script for displaying single rows
            <?
while($row = @mysql_fetch_array($result))
{

     $imageID = $row['imageID'];
     $imageName = $row['imageName'];
     $imageNameS = $row['imageNameS'];       
     $imageClientID = $row['imageClientID'];
       $imageBlurb = $row['imageBlurb'];
       $imageDate = $row['imageDate'];

$option_block .="<td><a href='admin/uploads/$imageName' target='blank'><img src='$imageNameS' height='100'></a></td>";

}
$display_block = "
<table><tr>
 $option_block  
  </tr></table>";
?>
0
jblayney
Asked:
jblayney
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1 Solution
 
jblayneyAuthor Commented:
ok, i tried this,i think im close.. no errors , but no output either

            <?
while($row = @mysql_fetch_array($result))
{

     $imageID = $row['imageID'];
     $imageName = $row['imageName'];
     $imageNameS = $row['imageNameS'];       
     $imageClientID = $row['imageClientID'];
       $imageBlurb = $row['imageBlurb'];
       $imageDate = $row['imageDate'];


$i = $row;
while ($i < 3) {
$option_block .="<tr><td><a href='admin/uploads/$imageName' target='blank'><img src='$imageNameS' height='100'></a></td>";
$i++;
$option_block .="</tr>";
}
$option_block .="</tr>";
}



$display_block = "
<table>
 $option_block  
</table>";
?>
0
 
jblayneyAuthor Commented:
ok, im even closer, my output now diplays an error and each image is displayed 3 times.. lol

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /u/j/jeremy/www.website.com/photopage.php on line 119
 
is my error

while($row = @mysql_fetch_array($result))
{

     $imageID = $row['imageID'];
     $imageName = $row['imageName'];
     $imageNameS = $row['imageNameS'];       
     $imageClientID = $row['imageClientID'];
       $imageBlurb = $row['imageBlurb'];
       $imageDate = $row['imageDate'];

$num_rows = mysql_num_rows($sql);
$i = $num_rows;
while ($i < 3) {
$option_block .="<td><a href='admin/uploads/$imageName' target='blank'><img src='admin/uploads/$imageNameS' height='100'></a></td>";
$i++;
$option_block .="</tr>";
}
$option_block .="</tr>";
}
$display_block = "
<table>
 $option_block  
</table>";
0
 
lozlozCommented:
hi,

i thought i'd try and do this as cleanly as possible:

<?
$j = 0;
print "<table>";
for($i = 0; $row = mysql_fetch_array($result) > $i; $i++) {
  if($j == 0) {
    print "<tr>";
  }
  print "<td><a href=\"admin/uploads/" . $row["imageName"] . "\" target='blank'><img src=\"" . $row["imageNameS] . "\" height=\"100\"></a></td>";
  if($j == 2) {
    print "</tr>";
    $j = -1;
  }
$j++;
}
$left = 3 - $j;
$k = 0;
if($left > 0) {
  for($k = 0; $k < $left; $k++) {
    print "<td>&nbsp;</td>\n";
  }
}
print "</table>";
?>

tell me how you get on

loz
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jblayneyAuthor Commented:
tx loz,
it is clean, one thign doesnt work though

print "<td><a href=\"admin/uploads/" . $row["imageName"] . "\" target='blank'><img src=\"admin/uploads/" . $row["imageNameS"] . "\" height=\"100\"></a></td>";

its displaying empty images and the links dont work, when you roll over with the mouse it displays the file path minus the filename
0
 
jblayneyAuthor Commented:
hey loz,
i rewrote the output 3 different ways, it all does the same thing, it gets the proper amount of results and displayes the tr and td properly, but its not getting the imageName and imageNameS,

Its like its this
I know their are 4 of you, but i dont know your names
0
 
lozlozCommented:
hmm that's strange can you do print_r($row); after each for statement and paste the html in here? (i.e. run the script > view source then copy the output and paste it here)

cheers,

loz
0
 
lozlozCommented:
well that leads me to suspect something in your query is amiss - can i see it? maybe you're not selecting the correct columns?

loz
0
 
jblayneyAuthor Commented:
ok, my SQL was select * but now i specified

$sql = "SELECT imageID, imageName, imageNameS FROM $table_name WHERE imageClientID = $id ORDER BY imageName";
            
$result = @mysql_query($sql, $connection) or die("Error3 - Couldn't connect - please try later.");

$j = 0;
print "<table>";
for($i = 0; $row = @mysql_fetch_array($result) > $i; $i++) {
print_r($row);
if($j == 0) {
print "<tr>";
}
print "<td><a href=\"admin/uploads/" .$row["imageName"]. "\" target='blank'><img src=\"admin/uploads/" .$row["imageNameS"]. "\" height=\"100\"></a></td>";


if($j == 2) {
print "</tr>";
$j = -1;
}
$j++;
}
$left = 3 - $j;
$k = 0;
if($left > 0) {
for($k = 0; $k < $left; $k++) {
print_r($row);
print "<td>&nbsp;</td>\n";
}
}
print "</table>";
?>

I added 2 print_r($row); and my HTML output is

<table>1<tr><td><a href="admin/uploads/" target='blank'><img src="admin/uploads/" height="100"></a></td>1<td><a href="admin/uploads/" target='blank'><img src="admin/uploads/" height="100"></a></td>1<td><a href="admin/uploads/" target='blank'><img src="admin/uploads/" height="100"></a></td></tr>1<tr><td><a href="admin/uploads/" target='blank'><img src="admin/uploads/" height="100"></a></td><td>&nbsp;</td>
<td>&nbsp;</td>
</table>
0
 
lozlozCommented:
try this:

<?
$j = 0;
print "<table>";
$num = mysql_num_rows($result);
for($i = 0; $num > $i; $i++) {
  $row = mysql_fetch_assoc($result);
  if($j == 0) {
    print "<tr>";
  }
  print "<td><a href=\"admin/uploads/" . $row["imageName"] . "\" target='blank'><img src=\"" . $row["imageNameS] . "\" height=\"100\"></a></td>";
  if($j == 2) {
    print "</tr>";
    $j = -1;
  }
$j++;
}
$left = 3 - $j;
$k = 0;
if($left > 0) {
  for($k = 0; $k < $left; $k++) {
    print "<td>&nbsp;</td>\n";
  }
}
print "</table>";
?>

loz
0

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