asked on

Copying retruned array

I am trying to return array to main and copy to another array.
--------------------------------
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
using namespace std;

int *Read_Input_File(char* generated_data_file)
{

const int KENO_NUM_SIZE = 80;
int keno_num_arrange_array[KENO_NUM_SIZE];
...
...
return keno_num_arrange_array;

}

int main()
{
int *temp_array[80];

char generated_data_file[] = "Keno_TC_2.dat";

temp_array = Read_Input_File(generated_data_file);
return 0;
}

--------------------
why am I having errors?

ASKER CERTIFIED SOLUTION

Sys_Prog

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SOLUTION

travd

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travd

Beat me by one minute. But note that it is not valid to use the variable keno_num_arrange_array in the main function since it has automatic storage duration and is destroyed on function exit.

SOLUTION

dennis_george

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DanRollins

I think all of the above are correct. However, the easiset way to to *not* return an array to main... rather create an array in main, and pass a pointer to that array to Read_Input_File():

bool Read_Input_File( char* szFile, int* anData ); // declare before using

void main()
{
int anData[80];
for (int j=0; j<80; j++ ) {
anData[j]= 0; // make sure all elements are zero
}
bool fRet= Read_Input_File( "c:\\Mydir\\Myfile.txt", anData ); // same as &anData[0]

for (int j=0; j<80; j++ ) {
cout << "Array index:" << j << " array item value: " << anData[j] <<endl;
}
}

bool Read_Input_File( char* szFile, int* anData )
{
... open the file ... see http:/Cplusplus/Q_20813330.html#9854643 for details
... read each line
... reach each datum into a string
... convert each string to a bunary int value...
int nValue= atoi( p );
if (nValue > 79 ) {
// this is an error, handle it
}
else {
anData[ nValue ]++; // indicate you got one more of these
}
}