Regular Expression that detects WORDS \w with no vowel in it

I can think of some parts needed to detect a word with no vowels in it, but can't figure out the whole thing (it's early!)..

I was thinking something along the lines of,


But thats not it...
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Tacobell777Author Commented:
You rock!

Stupid of me, ofcourse [^a|e|i|o|u] is a class so no OR | needed..

Ok, so your regex says

Non word characters - No aeiou At least once - Non word character

It doesn't make sense to me? It works, but I'd like to understand it too..

reg=new RegExp(/\W[^aeiou]+\W/)
alert(" abcd " + "\n" +reg.test(" abcd "))
alert(" wxyz " + "\n" +reg.test(" wxyz "))
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Thanks GfW
It says

Non word characters - a sequence of non aeiou's   - Non word character

ie having a vowel between the nonword chars returns false
Tacobell777Author Commented:
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