Solved

Sorting two single dimensional arrays

Posted on 2003-12-03
6
617 Views
Last Modified: 2010-03-31
I am having trouble sorting 2 arrays.  I must use single-dimensional arrays.  All I need to do is create 2 arrays - one for video titles and one for the inventory ID for each video title, sort by the inventory ID and print out the sorted list.  I am totally lost and think I really messed up my code now.  I had the program working up until the most important part (of course) - sorting and displaying the sorted video titles.  I know you can sort by object array, but can it be done the way I am trying??  My code is below:

public class Video
{
 public static void main(String[] args)
 {
  String[] videos = {"Lion King", "Holes", "Finding Nemo", "Beauty and the Beast", "Parent Trap"};
  int[] inventoryId = {102, 101, 104, 103, 100};
  int x;
  System.out.println("Unsorted movie titles:");
  for(x = 0; x < 5; ++x)
   System.out.println(inventoryId[x] + "    " + videos[x]);

public static void bubblesort(videos, int len)
{  
int a,b;
  Video temp;
  int lenMinusOne = len - 1;

//Sort by inventoryId
  for(a = 0; a < lenMinusOne; ++a)
    for(b = 0; b < lenMinusOne; ++b)
      if(array[b].inventoryId > array[b + 1].inventoryId)
      {
        temp = array[b];
        array[b] = array[b + 1];
        array[b + 1] = temp;
      }
   for(x = 0; x < 5; ++x)
   //System.out.println("Sorted movie titles:");
   System.out.println(inventoryId[x] + "    " + videos[x]);
 }
}
0
Comment
Question by:angelori
  • 3
  • 2
6 Comments
 
LVL 86

Accepted Solution

by:
CEHJ earned 400 total points
ID: 9868124
You need to swap both array values at the same time. I'll let you fill in the holes here:

public class Video
{
 public static void main(String[] args)
 {
  String[] videos = {"Lion King", "Holes", "Finding Nemo", "Beauty and the Beast", "Parent Trap"};
  int[] inventoryId = {102, 101, 104, 103, 100};
  int x;
  System.out.println("Unsorted movie titles:");
  for(int i = 0;i < inventoryId.length ;i++) {
    System.out.println(inventoryId[i]);

  }
  bubblesort(videos, inventoryId);
  for(int i = 0;i < inventoryId.length ;i++) {
      System.out.print(inventoryId[i] + ", ");
      System.out.println(videos[i]);

  }
 }

public static void bubblesort(String[] videos, int[] ids)
{
int a,b, temp;
String tempTitle;

//Sort by inventoryId
  for(a = 0; a < ids.length; a++)
    for(b = 0; b < a; b++)
      if(ids[a]  < ids[b])
      {
        tempTitle = videos[b];
        videos[b] = videos[a];
        videos[a] = tempTitle;
        temp = ids[b];
        ids[b] = ids[a];
        ids[a] = temp;
      }
 }
}
0
 
LVL 15

Expert Comment

by:JakobA
ID: 9869429
>> CEHJ:   I think you mean:

public static void bubblesort(String[] videos, int[] ids)  // boyh arrays to be sorted
{
int a,b, temp;
String tempTitle;
int lenMinusOne = videos.length -1;      // get length of arrats (minus one)

//Sort by inventoryId
  for(a = 0; a < lenMinusOne; a++)
    for(b = 0; b < lenMinusOne; b++)
      if(ids[a]  < ids[b])
      {
        tempTitle = videos[b];
        videos[b] = videos[a];
        videos[a] = tempTitle;
        temp = ids[b];
        ids[b] = ids[a];
        ids[a] = temp;
      }
 }
}

regards JakobA
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 9869469
>>I think you mean:

Do I? Why? ;-)
0
Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

 
LVL 15

Expert Comment

by:JakobA
ID: 9869476
actually we can cut the sorting time in half if we think a bit. notice how the inner loop alwat push the biggest value to the end of the array. no need to sort that value again:

public static void bubblesort(String[] videos, int[] ids)  // boyh arrays to be sorted
{
int a,b, temp;
String tempTitle;
int lenMinusOne = videos.length -1;      // get length of arrats (minus one)

//Sort by inventoryId
  for(a = lenMinusOne;  a>0 ;  a--)  //  a goes 'backwards'
    for(b = 0;  b < a;  b++)             //  b only sort up to a in each scan    
      if(ids[a]  < ids[b])
      {
        tempTitle = videos[b];
        videos[b] = videos[a];
        videos[a] = tempTitle;
        temp = ids[b];
        ids[b] = ids[a];
        ids[a] = temp;
      }
 }
}
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 9884671
8-)

JakobA's last optimization is good btw
0
 

Author Comment

by:angelori
ID: 9884676
Wow!  Thanks to both of you!  I consulted someone who is a Java programmer where I work and they were stumped too.  You 2 are awesome....Sorry about the length of time in accpeting the answer, etc.  This is my first time using this service.  
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Glassfish admin console not working 1 53
Selenium docs api java index 3 63
jmeter usage 4 31
Java array sort 10 26
By the end of 1980s, object oriented programming using languages like C++, Simula69 and ObjectPascal gained momentum. It looked like programmers finally found the perfect language. C++ successfully combined the object oriented principles of Simula w…
Java functions are among the best things for programmers to work with as Java sites can be very easy to read and prepare. Java especially simplifies many processes in the coding industry as it helps integrate many forms of technology and different d…
Video by: Michael
Viewers learn about how to reduce the potential repetitiveness of coding in main by developing methods to perform specific tasks for their program. Additionally, objects are introduced for the purpose of learning how to call methods in Java. Define …
This tutorial covers a practical example of lazy loading technique and early loading technique in a Singleton Design Pattern.

679 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question