Sorting based on numbers

Hi there,

Iam trying to make a sorting based on a counter but it seems that i get messup because when i try to sort some based on for example "3" all number that have a "3" will sorted as well and i dont want it. How can I sort ONLY the "3" and not the 13, 33, 23, 53, etc?
heres the code iam using

if ($yixa2 =~ 3) {
$tdtag3 = "</tr><tr>"; }
else {
$tdtag3 = "";
}

Any ideas?
Polos
polosAsked:
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ozoCommented:
if ($yixa2 == 3) {
0
ozoCommented:
$tdtag3 = $yixa2==3&&"</tr><tr>";
0

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rkosaiCommented:
It seems that you would best be served by placing this into a hash, then sorting the hash values by number.

For purposes of example, I am going to create a hash; you would use your own data here.
my %values;
$values{23} = 'caption0';
$values{13} = 'caption1';
$values{33} = 'caption2';
$values{3} = 'caption3';


You could then use this code to print the :

foreach(sort {$a <=> $b} keys %values) {
  print "<tr><td>$values{$_}</td><td>$_</td></tr>\n";
}

This would yield:

<tr><td>caption3</td><td>3</td></tr>
<tr><td>caption1</td><td>13</td></tr>
<tr><td>caption0</td><td>23</td></tr>
<tr><td>caption2</td><td>33</td></tr>

Which is what I think you're trying to accomplish.

Otherwise, if you're only trying to find the value "3" by itself, you can use the expression,

if ($x == 3) {
  #do action
}

Good luck.
0
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