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looking for shell to rename all files like ?????.dlm.???????.????.pip into ?????.dlm.pip.???????.????

Posted on 2003-12-04
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Last Modified: 2010-04-21
Thanks in advance,
-Al
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Question by:AlexF777
  • 2
4 Comments
 
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Expert Comment

by:shivsa
ID: 9877914
for i in `ls ??????.dlm.???????.????.pip`
do
   mv $i ?????.dlm.pip.???????.????
done


i am assuming that instaed of ? u have some charecter there.
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LVL 7

Expert Comment

by:glassd
ID: 9878488
I haven't tested this, so buyer beware.

$(ls ?????.dlm.???????.????.pip | awk '{
printf("mv %s %s%s%s\n",$0,substr($0,1,10),"pip",substr($0,10,13))
}')

the awk statement should print out three space separated fields for each line of input.
Field 1 is the string "mv" (the rename command).
Field 2 is the original filename (the whole line).
Field 3 is made up of the first 10 characters of the input file name (?????.dlm.), the string "pip", then the string starting with the 10th character of the filename, 13 characters long (.???????.????).

The input to the awk command is a list of all files of the required format (?????.dlm.???????.????.pip).

Finally, wrapping the whole lot in $(...) causes the shell (ksh or bash) to execute the output rather than just listing it to STDOUT.

Hope it works.
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LVL 38

Accepted Solution

by:
yuzh earned 200 total points
ID: 9880474
This following little script should do the job for you:

#!/bin/ksh

for i in `ls ??????.dlm.???????.????.pip`
    N1=`echo $i | cut -d "." -f 1`
    N2=`echo $i | cut -d "." -f 3`
    N3=`echo $i | cut -d "." -f 4`
    mv ${i} ${N1}.dlm.pip.${N2}.${N3}
done

echo "Job done, thanks !"
exit

#   END OF SCRIPT



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LVL 7

Assisted Solution

by:glassd
glassd earned 50 total points
ID: 9880568
Yes yuzh, using the period as the separator was so obvious that I missed it completely.

$(ls ?????.dlm.???????.????.pip | awk -F"."'{
printf("mv %s %s.%s.%s.%s.%s\n",$0,$1,$2,$5,$4,$3)
}')
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