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How to search a character in a string?

Posted on 2003-12-04
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Last Modified: 2010-05-01
Hi experts,

in my application, user need to enter a value before proceed. this value is needed to be put in a formula for calculation.. so this value need to be valid.

So if user put something like 1.23.4 (there are two dots), this is not a valid value anymore because i think VB cannot identify this value in calculation (mathematical).

How i want to code so that if user keyin more then one dot ("."), my application will pop up a msgbox indicate user to change the value. I already code for not allowed user to key in alphabet characters. so that is not a problem.. the problem only this dot ("."). i kindda think of to search the character "." , if it is more than one, so error msg will popup. But i don't know how to code it :)

thanks
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Question by:Diode_Temp
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5 Comments
 
LVL 18

Expert Comment

by:bobbit31
ID: 9878865
if it's a number you are looking for:

if IsNumeric(<value>) then
  '' it's a valid number
else
  '' it's not
end if
0
 
LVL 6

Expert Comment

by:prasitlee
ID: 9878993
Dear Diode_Temp,
    Try the following code. I am strongly sure that it would give you the idea to detect the number of dot which is greater than one.

Option Explicit

Private m_bDotExists As Boolean

Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer)
    If InStr(Text1.Text, ".") = 0 Then
        m_bDotExists = False
    Else
        m_bDotExists = True
    End If
End Sub

Private Sub Text1_KeyUp(KeyCode As Integer, Shift As Integer)
    If m_bDotExists Then
        If Mid(Text1.Text, Len(Text1.Text) - 1, 1) = "." Then
            MsgBox "More than one dot."
        End If
    End If
End Sub

    I am strongly sure that my comment has already answered your question.
                                                                                   Meng
0
 
LVL 14

Accepted Solution

by:
Tommy Kinard earned 80 total points
ID: 9879032
Hi Diode_Temp,

The below sub will display a message when the second decimal is entered.

Private Sub Text1_Change()
    If InStr(InStr(1, Text1.Text, ".") + 1, Text1.Text, ".") > 0 Then
        MsgBox "Invalid Data Entered!"
    End If
End Sub

HTH
dragontooth

0
 
LVL 86

Expert Comment

by:Mike Tomlinson
ID: 9880383
If your interested...this is my version of how to make a textbox that allows only a decimal value.  Negative values are allowed.  At any given time, there is always a valid number in the box.

Idle_Mind

Private Sub Form_Load()
    Text1.Text = "0"
    Text1.SelStart = 0
    Text1.SelLength = 1
End Sub

Private Sub Text1_KeyPress(KeyAscii As Integer)
    Dim insertPoint As Integer
    Dim char As String
   
    insertPoint = Text1.SelStart
    char = Chr(KeyAscii)
   
    If (KeyAscii >= 48 And KeyAscii <= 57) Then ' Digits 0 thru 9
        If KeyAscii = 48 Then
            If Text1.Text = "0" And Text1.SelStart = 0 And Text1.SelLength = 1 Then
                Text1.SelStart = 1
                Text1.SelLength = 0
                KeyAscii = 0
            ElseIf Text1.Text = "-0" And Text1.SelStart = 1 And Text1.SelLength = 1 Then
                Text1.SelStart = 2
                Text1.SelLength = 0
                KeyAscii = 0
            ElseIf Text1.Text = "-.0" And Text1.SelStart = 2 And Text1.SelLength = 1 Then
                Text1.SelStart = 3
                Text1.SelLength = 0
                KeyAscii = 0
            End If
        End If
        Exit Sub
    ElseIf KeyAscii = 8 Then ' BackSpace
        If Text1.Text = ".0" Then
            If (Text1.SelStart = 1 And Text1.SelLength = 1) Or Text1.SelStart = 2 Then
                Text1.Text = "0"
                Text1.SelStart = 0
                Text1.SelLength = 1
                KeyAscii = 0
            End If
        ElseIf Text1.Text = "-0" Then
            If Text1.SelStart = 1 And Text1.SelLength = 1 Then
                Text1.Text = "0"
                Text1.SelStart = 0
                Text1.SelLength = 1
                KeyAscii = 0
            End If
        ElseIf Text1.Text = "-.0" Then
            If Text1.SelStart = 2 And Text1.SelLength = 1 Then
                Text1.Text = "-0"
                Text1.SelStart = 1
                Text1.SelLength = 1
                KeyAscii = 0
            End If
        End If
        Exit Sub
    ElseIf char = "." Then
        If InStr(Text1.Text, ".") > 0 Then
            KeyAscii = 0
        End If
        Exit Sub
    ElseIf char = "-" Then ' Toggle Minus Sign
        If Left(Text1.Text, 1) = "-" Then
            Text1.Text = Mid(Text1.Text, 2)
            insertPoint = insertPoint - 1
        Else
            Text1.Text = "-" & Text1.Text
            insertPoint = insertPoint + 1
        End If
        Text1.SelStart = insertPoint
        KeyAscii = 0
        Text1_Change
        Exit Sub
    End If
    KeyAscii = 0 ' Cancel Everything Else
End Sub

Private Sub Text1_Change() ' Make sure we have a number in the box at all times
    Dim validChars As String
    Dim a As Integer
   
    validChars = "-.0123456789"
   
    If Text1.Text = "" Or Text1.Text = "0" Then
        Text1.Text = "0"
        Text1.SelStart = 0
        Text1.SelLength = 1
        Exit Sub
    ElseIf Text1.Text = "." Or Text1.Text = ".0" Then
        Text1.Text = ".0"
        Text1.SelStart = 1
        Text1.SelLength = 1
        Exit Sub
    ElseIf Text1.Text = "-." Or Text1.Text = "-.0" Then
        Text1.Text = "-.0"
        Text1.SelStart = 2
        Text1.SelLength = 1
        Exit Sub
    ElseIf Text1.Text = "-" Or Text1.Text = "-0" Then
        Text1.Text = "-0"
        Text1.SelStart = 1
        Text1.SelLength = 1
        Exit Sub
    End If
   
    ' code for handling when text is pasted into the box
    For a = 1 To Len(Text1.Text)
        If InStr(validChars, Mid(Text1.Text, a, 1)) = 0 Then
            Text1.Text = "0"
            Text1.SelStart = 0
            Text1.SelLength = 1
            Exit Sub
        End If
    Next a
   
    a = InStr(Text1.Text, "-")
    If a > 0 Then
        If InStr(a + 1, Text1.Text, "-") > 0 Then
            Text1.Text = "0"
            Text1.SelStart = 0
            Text1.SelLength = 1
            Exit Sub
        End If
    End If
   
    a = InStr(Text1.Text, ".")
    If a > 0 Then
        If InStr(a + 1, Text1.Text, ".") > 0 Then
            Text1.Text = "0"
            Text1.SelStart = 0
            Text1.SelLength = 1
            Exit Sub
        End If
    End If
End Sub
0
 
LVL 14

Expert Comment

by:Tommy Kinard
ID: 9882088
Glad I could help!
dragontooth

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