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conditional operator syntax

Posted on 2003-12-06
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Last Modified: 2010-05-01
I have string that contains information i want after the sixth comma, but the code i've written here won't return true for the if statement and goes into an infinite loop. Is the conditional operator syntax inaccurate?

intCommaCount = 0
x = 0
Do While intCommaCount < 6
        letter = Mid(stgFileToAppend, x, 0)
        If letter = "," Then
            intCommaCount = intCommaCount + 1
            x = x + 1
        Else
            x = x + 1
        End If
Loop
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Question by:sirjulio
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4 Comments
 
LVL 24

Expert Comment

by:R_Rajesh
ID: 9888029
Hi sirjulio,

str1 = "hello, how, do, you, do, my, dear"
s = Split(str1, ",")
MsgBox s(6)

here s(6) gives you the string after the sixth comma


Cheers!

Rajesh
0
 
LVL 24

Accepted Solution

by:
R_Rajesh earned 400 total points
ID: 9888053
the code you wrote can be modified like this:

intCommaCount = 0
x = 1
Do While intCommaCount < 6
letter = Mid(stgFileToAppend, x, 1)
If letter = "," Then
intCommaCount = intCommaCount + 1
End If
x = x + 1
Loop
finalstr = Right(stgFileToAppend, Len(stgFileToAppend) - x)
MsgBox finalstr



Rajesh
0
 
LVL 1

Author Comment

by:sirjulio
ID: 9888242
thanx rajesh

i overlooked that if i wanted the character to enter the string variable that the mid method's third variable (string length) has to be 1

u rock
0
 
LVL 24

Expert Comment

by:R_Rajesh
ID: 9888270
thanks for the grade :)
0

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