How to deal with big integer class?

/* Sqrt.java    11/12/03  
  it squares each previous squared result*/
import java.text.*;
import java.math.*;
import java.math.BigInteger;
public class Sqrt{
  public static void main(String[] args){
            long[] square = new  long[10];
            int ct;
            square[0]= 2*2;
           for(ct = 1; ct < 10; ct++)
           square[ct] = (long)Math.pow(square[ct-1], 2);
         for(int ct1 = 0; ct1 < 10; ct1++)  
         System.out.println(square[ct1]);
         }
      }
---------------------------------------------------------------------------------
Output:
4
16
256
65536
4294967296
9223372036854775807 (its actual result should be:18446744073709551616
9223372036854775807 (actual:3.4028236692093846346337460743177e+38)
9223372036854775807(actual:1.1579208923731619542357098500866e+77)
9223372036854775807(actual:1.3407807929942597099574024998193e+154)
9223372036854775807(actual:1.7976931348623159077293051907852e+308)
 
 Although I declared the data type as Long, it doesn`t output the right results since they`re out of the range that Long can handle.What kind of data type can handle those sort of humongous numbers?


edeita2Asked:
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edeita2Author Commented:
new output:
4.0
16.0
256.0
65536.0
4.294967296E9
1.8446744073709552E19
3.4028236692093846E38
1.157920892373162E77
1.3407807929942597E154
Infinity
 suggestion appreciated
dbruntonQuid, Me Anxius Sum?  Illegitimi non carborundum.Commented:
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