Logic problem

      int k;
      int m;
      TRACE("%d ",!(iNewPlace>=(sLine.length()-1)));      //outputs 1

      TRACE("%d ",iNewPlace);      //outputs 0
      TRACE("%d ",sLine.length()-1);      //outputs -1

      TRACE("%d ",((iNewPlace>=(sLine.length()-1))));      //outputs 0

      TRACE("%d ",((m=iNewPlace)>=(k=(sLine.length()-1))));      //outputs 1

      TRACE("%d ",0>=-1);      //outputs 1

      k=iNewPlace;
      m=sLine.length()-1;
      TRACE("%d ",k>=m);      //outputs 1

Why is TRACE("%d ",((iNewPlace>=(sLine.length()-1))));      outputting false?
ParticlenessAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

bcladdCommented:
iNewPlace and sLine.length() are unsigned. 0 - 1 is 0xffffffff which is -1 in two's compliment (signed int) but is a really big number as an unsigned int.

When the values are converted to integers (%d conversion or assignement to a signed int) you get signed comparison. Try comparing iNewPlace with m and I'll bet you get a signed/unsigned comparison warning from the compiler.

Hope this helps,
-bcl
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
ParticlenessAuthor Commented:
sLine.lenth() was unsigned, but iNewPlace was signed. Nevertheless you  helped me out.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C++

From novice to tech pro — start learning today.